Answer:
Step-by-step explanation:
The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function
g(x,y) = sin(π(x−5y)
∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))
(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]
(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]
∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j
∇g = π [cos (π(x−5y))] [î - 5j]
So, the question requires a direction vector and a point to fully evaluate this directional derivative now.
Neither one will ever hit the axis I think? if its x=3.5 then its horizontal but its above the x axis. Same with the second one. its vertical and will never hit the y axis. Not sure how to write that into those boxes but I think there isn't an intercept.
1. 156
2. 15.6
3. 1.56
You just move the decimal point in depending on the number or zeros.
9 then 8. You add 4 to each number then subtract 1. 5+4=9 9-1=8
Answer:
y= 0.6x + 6 or y= 3/5x + 6
Step-by-step explanation:
The function for a linear function is y=mx+b.
We know that b is 6 because that is the y-intercept.
However to find m we need to see how much the x coordinates skip on the table and the y coordinates. We can see that x coordinates skip by 5s and the y corrdinates skip by 3. We than divide 3/5 to get o.6 and we get the equation. This video, tittled "Writing A Linear Equation From A Function Table" explains it much better than I can.
