Which of the following is a convention of graph making? question 4 options:

WILL MARK BRAINLIEST IF ITS RIGHT !!

Furkat [3]

Answer:

Around 0.22

FIRST THOUGH, I FEEL LIKE 90 MIGHT HAVE MEANT TO BEEN 0.9, SO IF SO SUBSTITUTE THE 90 BELOW FOR 0.9!

Step-by-step explanation:

Okay, so first.

Company A will be 50 a day plus 0.4 a mile

Company B will be 30 a day plus 90 per mile

We can write an equation like this:

50 + 0.4m = 30 + 90m

m = miles they are the same

Then we solve for m.

50 + 0.4m = 30 + 90m

- 0.4m - 0.4m

50 = 30 + 89.6m

- 30 - 30

20 = 89.6m

Divide both sides by 89.6

Around 0.22!

5 0

3 years ago

What is the greatest common factor that could be used to reduce 36/90

TEA [102]

I got 18 for this one............

3 0

3 years ago

Read 2 more answers

A handyman charges a fixed rate of R to visit a customers house. In addition, the hardy man charges an hourly rate for H for eac

aksik [14]

Answer:

T == R + NH

Step-by-step explanation:

The fixed rate R is added to the hourly charges to get the total T. The hourly charges are the product of the number of hours and the charge per hour, NH.

The sum is then ...

... T = R + NH

4 0

3 years ago

The time required to complete a job varies inversely as the number of people working. it took 4 hours for 7 electricians to wire

Solnce55 [7]

Let's assign variables

The time required to wire a building: y

The number of electricians to have done this job: x


y varies inversely as x

so that:
$y= k\frac{1}{x}$
where k is the proportional constant

To calculate the value of k, plug in the values of x and y:
x=7
y=4

$4=k (\frac{1}{7}) \\~\\k=28$

Now, write down the relation between x and y:
$y=28x$

"how long would it have taken 3 electricians to have done the job?"
x=3
Let's find out y:
$y=(28) \frac{1}{3} = \frac{28}{3} =9 \frac{1}{3} =9.333333~~hr$

So it would take 9 hours and 20 minutes to have this job done.

3 0

3 years ago

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago