Answer:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus = ![\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BDiagonal%201%7D%29%28%5Ctext%7BDiagonal%202%7D%29)
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) = ![\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_2-x_1%29%5E%7B2%7D%2B%28y_2-y_1%29%5E2%20%7D)
Diagonal 1 (AC) =
= 4 units
Diagonal 2(BD) =
= 8 units
Now area of the rhombus ABCD = ![\frac{1}{2}(\text{AC})(\text{BD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BAC%7D%29%28%5Ctext%7BBD%7D%29)
= ![\frac{1}{2}\times 4\times 8](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%204%5Ctimes%208)
= 16 units²
Therefore, area of the given rhombus is 16 units².
Answer:
the answer is 10 you round up a nine it keeps going to the end
Answer:
0.25
Step-by-step explanation: