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Deffense [45]
3 years ago
14

Which of the following is the correct equation for the reaction below?

Chemistry
2 answers:
fenix001 [56]3 years ago
4 0

Answer:

Option C.

2 Mg (s) + O₂(g) →  2MgO (s)

Explanation:

Two moles of magnesium solid react with one mol of oxygen gas to

form two moles of magnesium-oxide solid

2 Mg (s) + O₂(g) →  2MgO (s)

That's the reaction for the magnessium oxide's formation.

Be careful cause we do not say molecules, they are moles.

The stoichiometry indicates the number of moles that react and the moles which are produced.

It is a redox reaction, because the magnessium is oxidized and the oxygen is reduced. Both elements, changed the oxidation states.

photoshop1234 [79]3 years ago
4 0

Answer: c is the answer

2 Mg (s) + O2 (g) ----> 2 MgO (s)!

Explanation:

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Fed [463]

Answer:

c

Explanation:

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3 years ago
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Can someone please explain this to me? I need help ​
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Answer:

The order would be: X-Rays, Visible Light, and Infrared Waves.

X-Rays have the shortest wavelength out of all three, then Visible Light, and Infrared Waves have the longest wavelength of the three.

Explanation:

So basically, the LONGER the wavelength, the lower the energy. and the SHORTER the wavelength, the higher the energy. For example, Radio waves are the WEAKEST out of all the types of waves because they have the LONGEST wavelengths. Gamma Rays are the STRONGEST out of all the types of waves because they have the SHORTEST wavelengths. So Radio Waves have the lowest energy, and Gamma Rays have the highest energy.

Here is a list of all the types of waves in order from shortest wavelength to longest wavelengths:

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6 0
3 years ago
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What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
Sliva [168]
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2


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6 0
3 years ago
During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

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3 years ago
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sergeinik [125]

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps

3 0
3 years ago
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