Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.
Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
To determine the empirical formula of ascorbic acid, we divide the lowest fraction with the other values. For this case, we divide everything with 3.406. We do as follows:
C = 3.407 / 3.406 = 1
H = 4.53 / 3.406 = 1.33
O = 3.406 / 3.406 = 1
So, you have CHO
Hope this answers the question. Have a nice day.
Answer:
2.08 moles
Explanation:
number of molecules = mass / molecular mass of SO₄
number of molecules = 200 g / 96.06 g/mol
number of molecules ≈ 2.08
