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3 years ago

10

(-11x+31y) - 2(-x + 5y)

1 answer:

Cerrena [4.2K]3 years ago

5 0

<u>Answer:</u>

Equivalent expression of (-11x+31y) - 2(-x + 5y) is -9x +21y Hence option C is correct

<u>Solution:</u>

Given expression is (-11x+31y) - 2(-x + 5y)

Need to find equivalent expression from four given option.

Let’s first simplify the given expression

(-11x+31y) - 2(-x + 5y)

On opening the brackets we get

-11x + 31y + 2x -10y

Now bringing similar terms together and performing appropriate operation, we get

-11x + 2x + 31y + -10y

Taking common terms out we get,

=> (-11 + 2) x + (31 -10) y

= -9x +21y

Therefore Equivalent expression of (-11x+31y) - 2(-x + 5y) is -9x +21y.

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Find the two square roots of each complex number by creating and solving polynomial equations.

son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3 + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

$\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))$

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i ⇒ r=17 θ= -0.4899 rad

w₁= $\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))$ =4-i

w₂= $\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))$ =-1+i

2) z = 8 − 6i ⇒ r=10 θ= -0.6435 rad

w₁= $\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))$ = 3 - i

w₂= $\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))$ = -3 + i

3) z = −3 + 4i ⇒ r=5 θ= -0.9316 rad

w₁= $\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))$ = 1 + 2i

w₂= $\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))$ = -1 - 2i

4) z = −5 − 12i ⇒ r=13 θ= 0.4426 rad

w₁= $\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))$ = 2- 3i

w₂= $\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))$ = -2 + 3i

5) z = 21 − 20i ⇒ r=29 θ= -0.8098 rad

w₁= $\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))$ = 5 - 2i

w₂= $\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))$ = -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁= $\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))$ = 5 - 3i

w₂= $\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))$ = -5 + 3i

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3 years ago

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Tamiku [17]

Answer:

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3 years ago

P is the set of even numbers that are less than 11

ivanzaharov [21]

Is there a restriction that the set must be positive? or whole numbers? Because negative numbers can be even, which makes your set an infinite list of numbers.

Natural numbers: P = {2, 4, 6, 8, 10}

Whole numbers: P = {0, 2, 4, 6, 8, 10}

All real numbers: P = {2n ;n ≤ 5}

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3 years ago

Why are handcuffs like souvenirs?

ArbitrLikvidat [17]

<u>Part A)</u> $7(a+b)=7a+$

Using the distributive property

$7(a+b)=7a+7b$

therefore

<u>the answer Part A is</u>

$9-----> A$

<u>Part R)</u> $4(5+x)=20+$

Using the distributive property

$4(5+x)=20+4x$

therefore

<u>the answer Part R is</u>

$14-----> R$

<u>Part Y)</u> $3(2x+9)=6x+$

Using the distributive property

$3(2x+9)=6x+27$

therefore

<u>the answer Part Y is</u>

$4-----> Y$

Part S) $8(3x+1)=+8$

Using the distributive property

$8(3x+1)=24x+8$

therefore

<u>the answer Part S is</u>

$23-----> S$

<u>Part O)</u> $a(4+b)=+ab$

Using the distributive property

$a(4+b)=4a+ab$

therefore

<u>the answer Part O is</u>

$17-----> O$

<u>Part E)</u> $x(y+10)=+10x$

Using the distributive property

$x(y+10)=xy+10x$

therefore

<u>the answer Part E is</u>

$3-----> E$

<u>Part I)</u> $2(7x+4y)=14x+$

Using the distributive property

$2(7x+4y)=14x+8y$

therefore

<u>the answer Part I is</u>

$20-----> I$

<u>Part D)</u> $6(9+5x)=54+$

Using the distributive property

$6(9+5x)=54+30x$

therefore

<u>the answer Part D is</u>

$10-----> D$

<u>Part W)</u> $x(a+3b)=+3bx$

Using the distributive property

$x(a+3b)=ax+3bx$

therefore

<u>the answer Part W is</u>

$18-----> W$

<u>Part E)</u> $a(8x+2y)=8ax+$

Using the distributive property

$a(8x+2y)=8ax+2ay$

therefore

<u>the answer Part E is</u>

$7-----> E$

<u>Part T)</u> $0.5(4a+10)=2a+$

Using the distributive property

<u>Part T)</u> $0.5(4a+10)=2a+5$

therefore

<u>the answer Part T is</u>

$1-----> T$

<u>Part R)</u> $(2/3)(12+9y)=8+$

Using the distributive property

$(2/3)(12+9y)=8+6y$

therefore

<u>the answer Part R is</u>

$6-----> R$

<u>Part O)</u> $5x+5y=5(x+\ )$

$5x+5y=5(x+y)$

therefore

<u>the answer Part O is</u>

$13-----> O$

<u>Part T)</u> $9a+9b=9(\ +b)$

$9a+9b=9(a+b)$

therefore

<u>the answer Part T is</u>

$22-----> T$

Part W) $4m+4n=\ (m+n)$

$4m+4n=4(m+n)$

therefore

<u>the answer Part W is</u>

$16-----> W$

<u>Part H)</u> $ab+3a=a(b+\ )$

$ab+3a=a(b+3)$

therefore

<u>the answer Part H is</u>

$2-----> H$

<u>Part E)</u> $xy+15x=\ (y+15)$

$xy+15x=x(y+15)$

therefore

<u>the answer Part E is</u>

$11-----> E$

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$bu+uv=u(b+v)$

therefore

<u>the answer Part A is</u>

$5-----> A$

<u>Part F)</u> $(2/5)m+(2/5)n=(2/5)( \ +n)$

$(2/5)m+(2/5)n=(2/5)(m+n)$

therefore

<u>the answer Part F is</u>

$12-----> F$

<u>Part M)</u> $(3/4)a+(3/4)b+(3/4)c=\ (a+b+c)$

$(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)$

therefore

<u>the answer Part M is</u>

$8-----> M$

<u>Part S)</u> $7ax+2ay=a(7x+\ )$

$7ax+2ay=a(7x+2y)$

therefore

<u>the answer Part S is</u>

$21-----> S$

Part T) $4kx+11ky=\ (4x+11y)$

$4kx+11ky=k(4x+11y)$

therefore

<u>the answer Part T is</u>

$15-----> T$

<u>Part R)</u> $3ay+8by=y(\ +8b)$

$3ay+8by=y(3a+8b)$

therefore

<u>the answer Part R is</u>

$19-----> R$

<u>the answer is</u>

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