The expected values of the binomial distribution are given as follows:
1. 214.
2. 21.
3. 31.
<h3>What is the binomial probability distribution?</h3>
It is the <u>probability of exactly x successes on n repeated trials, with p probability</u> of a success on each trial.
The expected value of the binomial distribution is:
E(X) = np
For item 1, the parameters are:
p = 3/7, n = 500.
Hence the expected value is:
E(X) = np = 500 x 3/7 = 1500/7 = 214.
For item 2, the parameters are:
p = 0.083, n = 250.
Hence the expected value is:
E(X) = np = 250 x 0.083 = 21.
For item 3, the parameters are:
p = 1/13, n = 400.
Hence the expected value is:
E(X) = np = 400 x 1/13 = 31.
More can be learned about the binomial distribution at brainly.com/question/24863377
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I'm not sure if this dividing,multiplying,subtracting or adding but for adding i got 6 as my answer.I don't know if this the correct answer but its better than having no answer right?
Answer:
x=9, y=10. (9, 10). The two numbers are 9 and 10.
Step-by-step explanation:
3x+5y=77
x+y=19
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3x+5y=77
-3(x+y)=-3(19)
---------------------
3x+5y=77
-3x-3y=-57
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2y=20
y=20/2
y=10
x+10=19
x=19-10
x=9
36/19
=1.894736842 and it keeps going
Hope this helped and have a great day!
