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Novay_Z [31]
4 years ago
6

Select all the discoveries that J. J. Thomson is credited with making.

Chemistry
2 answers:
goblinko [34]4 years ago
6 0
<span>subatomic particles neutrons isotopes electrons protons. subatomic particles isotopes electrons.</span>
tia_tia [17]4 years ago
4 0
Subatomic particles, isotopes, and electrons hope this helps and have a great Christmas.
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Landslides and slumps are forms of mass movements. Types of erosion both move, in different ways. In slumps, land breaks off in one piece, or chunk. Landslides are when rocks and dirt rapidly move down a slide.
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Find the empirical formula of the following compounds:<br> (c) A hydrocarbon with 79.9 mass % carbon
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The compound is 82.76% C and 17.24% H

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Describe the empirical formula.</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea.

The simplest whole number ratio of each type of atom in a compound is its empirical formula. It can be determined from data on the mass of each component in a compound or from the composition's proportion.

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2 years ago
What type of battery is your flashlight battery?
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4 0
3 years ago
What house items is similar to gall bladder, pancreas, brain, and spinal cord
fenix001 [56]

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8 0
3 years ago
A chemistry graduate student is given 125.mL of a 0.20M acetic acid HCH3CO2 solution. Acetic acid is a weak acid with =Ka×1.810−
Over [174]

Answer : The mass of sodium acetate is, 1.097 grams.

Explanation : Given,

The dissociation constant for acetic acid = K_a=1.8\times 10^{-5}

Concentration of acetic acid (weak acid)= 0.20 M

volume of solution = 125. mL

pH = 4.47

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.8\times 10^{-5})

pK_a=5-\log (1.8)

pK_a=4.74

Now we have to calculate the concentration of sodium acetate (conjugate base or salt).

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

4.47=4.74+\log (\frac{[Salt]}{0.20})

[Salt]=0.107M

Now we have to calculate the mass of sodium acetate.

\text{Concentration}=\frac{\text{Mass of }NaCH_3CO_2\times 1000}{\text{Molar mass of }NaCH_3CO_2\times \text{Volume of solution (in mL)}}

0.107M=\frac{\text{Mass of }NaCH_3CO_2\times 1000}{82g/mol\times 125mL}

\text{Mass of }NaCH_3CO_2=1.097g

Therefore, the mass of sodium acetate is, 1.097 grams.

6 0
4 years ago
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