Select all the discoveries that J. J. Thomson is credited with making.
2 answers:
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Answer: Reducing agent in the given reaction is .
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in is +2 and
has 0 oxidation state.
In oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is .
Answer:
The degree of dissociation of acetic acid is 0.08448.
The pH of the solution is 3.72.
Explanation:
The
The value of the dissociation constant =
Initial concentration of the acetic acid = [HAc] =c = 0.00225
Degree of dissociation = α
Initially
c
At equilibrium ;
(c-cα) cα cα
The expression of dissociation constant is given as:
Solving for α:
α = 0.08448
The degree of dissociation of acetic acid is 0.08448.
The pH of the solution ;