Answer:
[N₂] = 0.032 M
[O₂] = 0.0086 M
Explanation:
Ideal Gas Law → P . V = n . R . T
We assume that the mixture of air occupies a volume of 1 L
78% N₂ → Mole fraction of N₂ = 0.78
21% O₂ → Mole fraction of O₂ = 0.21
1% another gases → Mole fraction of another gases = 0.01
In a mixture, the total pressure of the system refers to total moles of the mixture
1 atm . 1L = n . 0.082L.atm/mol.K . 298K
n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles
We apply the mole fraction to determine the moles
N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂
O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂
Answer:
Approximately 22.37 days, will it take for the water to be safe to drink.
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
k is rate constant
Given that:- k = 0.27 (day)⁻¹
= 0.63 mg/L
mg/L
Applying in the above equation as:-
![63e^{-0.27t}=150\times \:10^{-3}](https://tex.z-dn.net/?f=63e%5E%7B-0.27t%7D%3D150%5Ctimes%20%5C%3A10%5E%7B-3%7D)
![e^{-0.27t}=\frac{1}{420}](https://tex.z-dn.net/?f=e%5E%7B-0.27t%7D%3D%5Cfrac%7B1%7D%7B420%7D)
![t=\frac{100\ln \left(420\right)}{27}=22.37](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B100%5Cln%20%5Cleft%28420%5Cright%29%7D%7B27%7D%3D22.37)
<u>Approximately 22.37 days, will it take for the water to be safe to drink.</u>
Answer:
1.
643.21g 1 mol 6.022^23
262.87 g 1 mol
= 1.4735E24 [Mg3(PO4)2]
2.
4.061x10^24 1mol 22.4 (L)
6.022^23 1mol
= 151 liters H2O2
3.
479.3g 1 mol 6.022^23
18.02g 1mol
= 1.60E25 H20 atoms
4.
80.34L 1mol 164.1
22.4L 1mol
588.6g Ca(NO3)2
5.
893.7g 1mol 22.4
44.01g 1mol
= 427 L CO2 or 427.4
6.
5.39 x 10^25 1mol 78.01
6.022^23 1mol
= 6980g Al(OH)3
hope this helps!! :)
Answer:
Akash
Explanation:
it could be a magnet with the same poles facing eachoher
Answer:
dont just go off of me because im not sure but i think its c
Explanation: