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r-ruslan [8.4K]
2 years ago
11

The density of lithium is 0. 546 g/cm3. what volume is occupied by 3. 66 x 10 23 atoms of lithium?

Chemistry
1 answer:
s344n2d4d5 [400]2 years ago
3 0

The volume occupied by 3.66 x 10^{23} atoms of lithium is 7.73 cm^3

<h3>What is Density?</h3>

The density of a substance is defined as the mass of the substance per unit volume. It is often denoted by the symbol ρ

The density of a substance is given by,

\rho = \frac{m}{V}

The mass of a substance is the measure of the amount of matter present in it. It is generally measured in grams (g) or kilograms (kg).

The volume of a substance is defined as the amount of 3D space occupied by it.

<h3>What is Mole Concept?</h3>

It is a concept which uses mole as a unit to measure the number of atoms, molecules or ions.

A mole is defined as the amount of substance which has the same number of elementary particles as there are atoms in 12 grams of \ce{^{12}C}

1 mole = Avogadro's number = 6.022 x 10^{23\\ atoms

<h3>Steps to find out the volume</h3>

Molar Mass of Lithium = 6.94 g/mol

1 mole of Lithium has 6.022 x 10^{23} atoms

3.66 x 10^{23} atoms of lithium has molar mass = \frac{6.94 g}{6.022\times10^{23} } \times 3.66 \times 10^{23}

m = 4.218 g

Substitute in density formula,

\rho = \frac{m}{V}

V = \frac{m}{\rho}

=\frac{4.218g}{0.546g/cm^3}

= 7.73 cm^3\\

Therefore, 3.66 x 10^{23} atoms of lithium occupies 7.73 cm^3\\ of volume.

Learn more about the mole concept:

brainly.com/question/1427235

#SPJ4

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