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loris [4]
3 years ago
13

If you had excess chlorine, how many moles of of aluminum chloride could be produced from 19.0 g of aluminum?

Chemistry
2 answers:
puteri [66]3 years ago
7 0

Answer: 0.70 moles

Explanation:

2Al+3Cl_2\rightarrow 2AlCl_3

As can be seen from the chemical equation, 2 moles of aluminium react with 3 moles of chlorine.

According to mole concept, 1 mole of every substance weighs equal to its molar mass.

Moles of Al =\frac{\text{ given mass of Al}}{\text{ molar mass of Al}}= \frac{19g}{27g/mole}=0.70moles

As aluminium is the limiting reagent as it limits the formation of product and chlorine is the excess reagent as it is left unreacted.

2 moles of aluminium reacts to produce 2 moles of aluminium chloride.

0.70 of aluminium reacts to form =\frac{2}{2}\times 0.70=0.70moles of aluminium chloride.

Thus 0.70 moles of aluminium chloride will be formed.

SIZIF [17.4K]3 years ago
5 0
The chemical reaction would be written as follows:

2Al + 3Cl2 = 2AlCl3

We are given the amount of aluminum to be used in the reaction. This will be the starting point of the calculations. We do as follows:

19.0 g Al ( 1 mol / 29.98 g ) ( 2 mol AlCl3 / 2 mol Al ) = 0.63 mol AlCl3
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The color is an effect as a result of different wavelengths and frequencies of the light waves. So, color is a property of an object that depends on the wavelength.  From all the given statements the following is true: T<span>he color depends upon the lighting source. More precisely, the color depends upon the wavelength of the lighting source.</span>
5 0
3 years ago
What is the pH of a solution of 0.800 M KH2PO4, potassium dihydrogen phosphate?
Nookie1986 [14]
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
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3 0
3 years ago
How many moles of each element (C, H, and O) are present in a 100.0 g sample of<br> ethanol?
Anuta_ua [19.1K]

Answer:

2.173 moles of ethanol is presented in a 100.0g sample of ethanol .

Explanation:

The amount of substance that contains as many Particles as there are atoms in exactly 12g of carbon- '12 isotope is called 1 mole '= 46 u.

7 0
3 years ago
If you answer in 10 minutes you'll get 50 points
lisabon 2012 [21]

Answer:

grams

Explanation:

5 0
3 years ago
Read 2 more answers
If you have 5 moles of carbon dioxide at 30degrees C and under 600mmHg of pressure, what will the volume be
trapecia [35]

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 30 °C

T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

600 mmHg = 600 mmHg × 1 atm / 760 mmHg

600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

7 0
3 years ago
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