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3 years ago

Based on the formulas, select the compounds that are covalent.

Chemistry

2 answers:

madam [21]3 years ago

8 0

Answer : The covalent compounds are, SiF₄, CO₂, S₇O₂, PCl₃, H₂O and S₂F₁₀

Explanation :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

KBr

It is an ionic compound because potassium element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

SiF₄

It is a covalent compound because sharing of electrons takes place between silicon and fluorine. Both the elements are non-metals and hence, will form covalent bond.

Al₂O₃

It is an ionic compound because aluminum element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

CO₂

It is a covalent compound because sharing of electrons takes place between carbon and oxygen. Both the elements are non-metals and hence, will form covalent bond.

NaCO₃

It is an ionic compound because sodium element is a metal and carbon element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

S₇O₂

It is a covalent compound because sharing of electrons takes place between sulfur and oxygen. Both the elements are non-metals and hence, will form covalent bond.

PCl₃

It is a covalent compound because sharing of electrons takes place between phosphorus and chlorine. Both the elements are non-metals and hence, will form covalent bond.

Fe₃N₂

It is an ionic compound because iron element is a metal and nitrogen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

H₂O

It is a covalent compound because sharing of electrons takes place between hydrogen and oxygen. Both the elements are non-metals and hence, will form covalent bond.

S₂F₁₀

It is a covalent compound because sharing of electrons takes place between sulfur and fluorine. Both the elements are non-metals and hence, will form covalent bond.

Hence, the covalent compounds are, SiF₄, CO₂, S₇O₂, PCl₃, H₂O and S₂F₁₀

Sedbober [7]3 years ago

3 0

S2F10, FE3N2, S7O2, NaCO3, Al2O3, PC13, and CO2. Hope this helps

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Answer:

a) LAW OF MULTIPLE PROPORTIONS

b) 0.095g, 0.71g, 0.285g respectively

c) X2Y, YZ15, X6Y

d) hence mass of compound X = 21 x 0.045 = 0.95g

mass of compound Y = 21 x 0.955 = 20.05g

Explanation:

a) The assumptions made in solving this questions is the application of the LAW OF MULTIPLE PROPORTIONS. The Law of multiple proportions states that if two elements A and B combine together to form more than one compound, then the several masses of A which chemically combine with a fixed mass of B is in a simple ratio.

for example, copper forms two oxides ; copper(I) oxide (CuO) and copper(ii) oxide(Cu2O), it is possible for the two samples of the oxides to be reduced to Cu by reacting with Hydrogen gas. as such, certain masses of oxygen combine separately with a fixed mass of Cu. then the ratios of Cu are then determined.

b) To calculate the relative masses, we take note of the three compounds given, they all have some amount of Y in them, hence we can use Y as our relative mass, this implies that the relative mass of Y = 1g

mass of X = 0.4g

mass of Y = 4.2g

amount of X in 1g of Y = 0.4 x 1 /4.2

= 0.095g

for compound 2;

mass of Y = 1.4g

mass of Z = 1.0g

amount of Z in 1g of Y =1.0 x 1 /1.4

= 0.71g

for compound 3;

mass of X = 2.0g

mass of Y = 7.0g

amount of X in 1g of Y = 1 x 2/7

= 0.285g

c) Applying the law of multiple proportions; since elements X and Z combine with a fixed mass of Y, they must bear a simple ratio;

compound 1/compound 3 = 0.095/0.285

= 1/3

compound 1/compound 2 = 0.095/0.71

= 2/15

compound 2/ compound 3 = 0.71/0.285

= 5/2

formular for compound 1 = X2Y

formula for compound 2 = YZ15

formular for compound 3 = X6Y

d) from the formular X2Y, we can get the amount of each product in XY using the ratios

%of compound XY in X = mass of compound X / total Mass

= 0.2/4.4 = 4.5%

as such in a 21g of compound XY, %of compound Y = 1 - %of compound X = 95.5%

hence mass of compound X = 21 x 0.045 = 0.95g

mass of compound Y = 21 x 0.955 = 20.05g

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