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hoa [83]
3 years ago
11

Water molecules are ____________ because the hydrogen atoms are positively charged on one end and the oxygen atoms are negativel

y charged on one end. Molecules that are ____________ share electrons equally. Sodium chloride (NaCl) is an example of a ____________ molecule because it is soluble in water. Molecules that are ____________ are insoluble in water. It is ____________ that most molecules formed with nonpolar bonds dissolve easily in water.
Chemistry
1 answer:
iragen [17]3 years ago
8 0

Answer:

What is your question?

High School Chemistry 10+5 pts

Water molecules are _____polar_______ because the hydrogen atoms are positively charged on one end and the oxygen atoms are negatively charged on one end. Molecules that are _____nonpolar_______ share electrons equally. Sodium chloride (NaCl) is an example of a ______polar______ molecule because it is soluble in water. Molecules that are _____nonpolar_______ are insoluble in water. It is ______false______ that most molecules formed with nonpolar bonds dissolve easily in water.

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A4 kg object is being pulled to the east by a 6 N force. What is the object's<br> acceleration?
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1.5 ms⁻²

Explanation:

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A science teacher asked students to calculate the density of a toy block. The mass of the block was 110 grams and the volume of
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Starch and cellulose are both produced by plants, yet one is easily digested by animals and the other is not. Discuss the differ
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Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
2 years ago
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