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HACTEHA [7]
2 years ago
9

What is the value for AG at 100 K if AH = 27 kJ/mol and AS = 0.09 kJ/mol.K)?

Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
5 0

The value for ΔG = 18 kJ/mol

<h3>Further explanation</h3>

Given

ΔH = 27 kJ/mol and ΔS = 0.09 kJ/mol.K

T = 100 K

Required

the value for ΔG

Solution

The spontaneous process of a reaction is based on 2 factors :

  • enthalpy change ΔH decreases and
  • entropy change ΔS increases

ΔG=ΔH-T.ΔS

\tt \Delta G=27~kJ/mol-100\times 0.09~kJ/mol.K\\\\\Delta G=18~kJ/mol

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What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?
faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

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a) -278 x 10^{-23}J/T

b) 3.71 x 10^{-23}J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

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3 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

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mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

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mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

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S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

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3 years ago
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