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3 years ago

With

1 answer:

3 0

<span>y - 2418.6 = 5.9(x - 54)
y - 2418.6 = 5.9x - 318.6
y = 5.9x + 2100
f(x) = 5.9x + 2100 (this is our function)
.
Now we can answer:
What is the weight of the plane with 26 gallons of fuel in its tank?
f(26) = 5.9(26) + 2100 = 2253.4 pounds
(Put me as brainiest!!!! <3)</span>

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Solve the following systems of equations 2a+4b+c=5 ; a-4b=-6 ; 2b+c=7.

SOVA2 [1]

Answer:

a = -2

b = 1

c = 5

Step-by-step explanation:

Given:

2a + 4b + c = 5 ............(1)

a - 4b = - 6

a = 4b - 6 .............(2)

2b + c = 7

c = 7 - 2b ...........(3)

substituting 2 and 3 in 1, we get

2(4b - 6 ) + 4b + (7 - 2b) = 5

8b - 12 + 4b + 7 - 2b = 5

10b - 5 = 5

b = 1

substituting b in 2, we get

a = 4(1) - 6

a = -2

substituting b in 3, we get

c = 7 - 2(1)

c = 5

thus,

a = -2

b = 1

c = 5

8 0

3 years ago

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago

HELP PLEASE

frozen [14]

Answer:

it would take seven and a half hours

Step-by-step explanation:

450 ÷60 =7.5

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3 years ago

Use the distributive property to demonstrate that the product of 10 and -1/5 is a negative number. Make sure to include all step

rodikova [14]

-1(10 * (-1/5))

(-10)(1/5)

-2

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3 years ago

Someone help me multiple choice!!! <br> questions 1-5!!!

lesantik [10]

Answer:B,C,A,C.

Step-by-step explanation:

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1 year ago