Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
Answer:
Please check the explanation.
Step-by-step explanation:
Given the sequence
2, 6, 10, 14, 18
An arithmetic sequence has a constant difference and is defined as
compute the differences of all the adjacent terms
The difference between all the adjacent terms is the same.
Thus,
and
Therefore, the nth term is computed by:
Thus, position to term rule of 2, 6, 10, 14, 18 multiply by __4___ and subtract by __2__.
Answer: 2/3
Explanation: the difference between -14 and -10 is 4 and in fractions x/y. so we have 4/y. the difference between -18 and -12 is 6 so we have 4/6 but we can simplify that to 2/3.
Answer:
no, the confidence interval for the standard deviation σ cannot be expressed as 15.7 
4.7There are three ways in which you can possibly express a confidence interval:
1)
inequalityThe two extremities of the interval will be each on one side of the "less then" symbol (the smallest on the left, the biggest on the right) and the symbol for the standard deviation (σ) will be in the middle:
11.0 < σ < 20.4
This is the first interval given in the question and it means <span>that the standard deviation can vary between 11.0 and 20.4
2)
interval</span>The two extremities will be inside a couple of round parenthesis, separated by a comma, always <span>the smallest on the left and the biggest on the right:
(11.0, 20.4)
This is the second interval given in the question.
3)
point estimate </span><span>
margin of error</span>
This is the most common way to write a confidence interval because it shows straightforwardly some important information.
However,
this way can be used only for the confidence interval of the mean or of the popuation, not for he confidence interval of the variance or of the standard deviation.
This is due to the fact that in order to calculate the confidence interval of the standard variation (and similarly of the variance), you need to apply the formula:
which involves a χ² distribution, which is not a symmetric function. For this reason, the confidence interval we obtain is not symmetric around the point estimate and the third option cannot be used to express it.
