Raising the hook, or load by exactly 1 meter, will allow the length of the compressed material regain its original length, provided it wasn't deformed by the 5% compression.
<h3>Hooke's law </h3>
Hooke's law states that the force applied to an elastic material is directly proportional to the extension of the material provided that the elastic limit of the material is not exceeded.
When the length of the material is compressed by 5%, the material will regain its original size and shape when the applied load is removed, if the material was not deformed by the compression.
Thus, raising the hook, or load by exactly 1 meter, will allow the length of the compressed material regain its original length, provided it wasn't deformed by the 5% compression.
Learn more about Hooke's law here: brainly.com/question/2648431
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N
Red is refracted the least and violet is refracted the most
The acceleration due to gravity is 3 m/s^2 and the work done is -4.3 J.
<h3>What is the acceleration due to gravity?</h3>
Now we must use the formula;
h = ut + 1/2gt^2
Since it was dropped from a height u = 0 m/s
h = height
u = initial velocity
g = acceleration due to gravity
t = time
h = 1/2gt^2
g = 2h/t^2
g = 2 * 2.85 /(1.38)^2
g = 5.7/1.9
g = 3 m/s^2
The work that must be done is against gravity hence;
W = -(mgh)
W = - (0.5 kg * 3 m/s^2 * 2.85 m)
W = - 4.3 J
Learn more about acceleration due to gravity:brainly.com/question/13860566
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Answer:
u have to add all the numbers and then round it to the nearest ten
Explanation: