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White raven [17]
2 years ago
14

Acceleration is always measured in meters per second squared. Why is acceleration not measured in meters per second like speed?

Explain.
Physics
1 answer:
Taya2010 [7]2 years ago
6 0

Answer:

Because 'distance per second' is a velocity, not an acceleration.

Explanation:

Because 'distance per second' is a velocity, not an acceleration. For example, at 1 m/s an object is travelling a distance of 1 metre every second. But a rate of acceleration is a steady increase in velocity. So at 1 m/s^2, an object's velocity is increasing by 1 m/s every second.

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Two waves overlap producing a new wave that exhibits destructive
suter [353]

Answer:B

Explanation:

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3 years ago
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Find the velocity, acceleration, and speed of a particle with the given position function. r(t = t2i 6tj 4 ln t k
artcher [175]
1st derivative gives velocity;
d r(t)/ dt = 2t i + 6 j + 4/t k

2nd derivative gives acceleration;
d^2 r(t)/ dt^2 = 2 i - 4/ t^2

Speed ;
Square root of (4 t^2 + 36 + 16/ t^2)

For a given time, like 2 seconds, t will be 2. And answer of speed will be scalar.
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3 years ago
If the distance between the first order maximum and the tenth order maximum of a double-slit pattern is 18 mm and the slits are
Setler79 [48]

Answer:

Wavelength of light is 600 nm

Explanation:

Given

Distance between the first order maximum and the tenth order maximum of a double-slit pattern = 18 mm

Separation between the slits = 0.15 mm

Distance of screen from the slits = 50 cm

Wavelength

= \frac{18*10^{-3} * 0.15 *10^{-3}}{0.50*9} \\= 6 *10^{-7}\\= 600nm

4 0
2 years ago
What is the state of y when y = k/x, x is halved.
tangare [24]

Answer:

y becomes doubled.

Explanation:

If;

       y  = \frac{k}{x}  

what is the state of y when x is halved;

  the given expression is an inverse relationship. When y increases, x is supposed to decrease and vice versa.

 

 if x is halved; x  = \frac{x}{2}

           \frac{k}{\frac{x}{2} }   = \frac{2k}{x}  

Now compare :

      \frac{k}{x}  :  \frac{2k}{x}

we see that y becomes doubled

8 0
3 years ago
A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
rjkz [21]

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

3 0
2 years ago
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