two objects are thrown from the top of a tall building and experience no appreciable air resistance. one is thrown up and the ot
2 answers:
Answer:
Final speeds are equal to each other.
Explanation:
Both objects experiment a change in their velocities because of gravity. Let model each object by following equations:
Object A - Throw Up
Object B - Throw Down
Where is the height difference between the top of the building and the street. Let consider upward speed positive.
Final speeds are equal to each other.
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We calculate current from the formula:
, where q is a electric charge transferred over time t
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I=
Result is in unit-Ampere
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I=
<h2>Answer:</h2>
400N/m
<h2>Explanation:</h2>When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e
= ∑ⁿ₁ [
] -----------------------(i)
That is;
=
+
+
+ . . . +
-------------------(ii)
If they have the same value of stiffness say s, then equation (ii) becomes;
= n x
-----------------(iii)
Where;
n = number of springs
From the question,
There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;
n = 3
s = 1200N/m
Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;
= 3 x
=
=
Cross multiply;
m = 400N/m
Therefore, the stiffness of the longer spring is 400N/m