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Nimfa-mama [501]
3 years ago
10

What can hold a greater volume of water than a mug

Physics
2 answers:
Volgvan3 years ago
7 0
A jug would hold more volume than a mug
Degger [83]3 years ago
3 0
I have a few options,

Bowl, Pot, Jug

Hope this helps :))
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In the product 6o2 what does the coefficient mean
Lostsunrise [7]

Answer:

a numerical or constant quantity placed before and multiplying the variable in an algebraic expression example ( 4 in 4x y).

Explanation:

Hope this helps! Brainly if so!

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3 years ago
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Which of the following is a negatively charged particle that is found in "clouds" around the nucleus?
shutvik [7]
The answer is electron



Explanation: An atom consists of a small but massive nucleus that include protons (positive charge) and neutrons (neutral charge). around the nucleus is a cloud of rapidly moving electrons (negative charge)
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One or more calcium ions (Ca+2) combine with one or more chlorine ions (Cl-1). What is the resulting formula?
N76 [4]
The formula is CaCl2 as you need two Cl ions in order to combine with one Ca ion in order to form a neutral compound i.e. You need to have the same amount of charges therefore  you have two Cl ions which have  -1 charges for one +2 Ca ion.
Hope this helps :).
5 0
3 years ago
Pulmonary circulation involves blood flow to and from the heart and the ____?
olga nikolaevna [1]
I believe the answer would be lungs
3 0
3 years ago
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A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 3 m/s to catch the man. How far w
inessss [21]

Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is v=\frac{d}{t}, where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is d=v\cdot t

Now, the distance equation for the man would be:

d_{man}=v_{man}\cdot t=1.6\cdot t

The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

d_{dog}=v_{dog}\cdot (t-1.8)=3\cdot (t-1.8)

For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:

d_{dog}=v_{dog}\cdot (1.8-1.8)=3\cdot (0)=0

Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.

d_{man}=d_{dog}

1.6\cdot t=3\cdot (t-1.8)

1.6\cdot t=3\cdot t-5.4

1.4\cdot t=5.4

t=\frac{5.4}{1.4}

t=3.8571s

The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.

That value is used in the man's distance equation.

d_{man}=1.6\cdot t=1.6\cdot (3.8571)

d_{man}=6.1714m

Finally, the dog catches up with the man 6.1714m later.

6 0
3 years ago
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