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just olya [345]
3 years ago
13

Two gas samples have the same number of molecules, the same volume, and the same pressure. Which of the following could be true?

A. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0o C. B. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 298 K. C. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 273o C. D. The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 100o C.
Chemistry
2 answers:
IRISSAK [1]3 years ago
4 0
The correct answer is (A): The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0 C.

bulgar [2K]3 years ago
3 0
Lets name one gas sample as A and other gas sample as B.
we can apply ideal gas law equation for both samples
PV = nRT
P - Pressure of A = Pressure of B
V - volume of A = volume of B
n  - number of molecules of both A and B being equal is equivalent to number of moles of A = number of moles of B
R - universal gas constant
Tᵃ - temperature of A
Tᵇ - temperature of B
for gas A
PV = nRTᵃ  --1)
for gas B
PV = nRTᵇ  ---2)
when we divide both equations 
1 = Tᵃ  / Tᵇ
Tᵃ = Tᵇ
both temperatures are equal 
temperature in Celsius + 273 = temperature in Kelvin
therefore 0 °C = 273 K 
the correct answer is 
A)
<span>The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0 </span>°<span>C</span>
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Answer:

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Explanation:

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On the other hand, a dependent variable is the variable that responds to the manipulation of the independent variable. In other words, it is the outcome of the experiment. In this experiment, the BREAKING DISTANCE is the responding or dependent variable.

Constant or controlled variable is that variable that is kept constant or unchanged throughout the course of the experiment. The constant, if changed, will influence the result of the experiment. The constant in this experiment is the CAR since the same car (unchanged) was used for the experiment.

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Explanation:

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The following reaction was performed in a sealed vessel at 791 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at
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Answer:

4.31 × 10²

Explanation:

Equation of the reaction;

H_{2(g)} + I_{2(g)}     ⇌     2HI_{(g)

The ICE Table is shown as follows:

                            H_{2(g)}         +         I_{2(g)}        ⇌     2HI_{(g)

Initial                    3.10                     2.50                  0      

Change                 - x                       -x                     + 2x      

Equilibrium        (3.10 - x)                0.0800              2x

From I_{2(g)}   ;

We can see that 2.50 - x = 0.0800

So; we can solve for x;

x = 2.50 - 0.0800

x = 2.42

H_{2(g)}  which = (3.10 -x) will be :

= 3.10 - 2.42

= 0.68

2HI_{(g) = 2x

= 2 (2.42)

= 4.84

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K_c =\frac{23.4256}{0.0544}

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