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zavuch27 [327]
2 years ago
14

This is a test please help

Chemistry
1 answer:
GenaCL600 [577]2 years ago
3 0

Answer:

remaining still during the night.

Explanation:

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Answer: i would say producer

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How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol
mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

2Al + 3Cu{(NO_3)}_2  \rightarrow 2Al{(NO_3)}_3 +3 Cu

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

Al \rightarrow Al^{3+} + 3e^-

And copper goes from +2 to 0

Cu^{2+} + 2e^-\rightarrow Cu

On balancing the number of electrons we get:

For 1 mole of Al 6e^- is required.

Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

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1 year ago
What happens when potassium metal react with nitric acid
Marrrta [24]

Answer:

Astamañana vaya buenas noches

3 0
3 years ago
Which of these describes an endothermic process?
Phoenix [80]
The third one down: "When barium hydroxide is mixed with ammonium chloride, ice crystals form on the outside of the container."

This is because an endothermic reaction [process] takes in more energy than it releases. Therefore because a decrease in energy leads to a decrease in temperature, the ice crystals forming show that it must be a endothermic reaction [process].

Hope this helps! :)
AJ
3 0
3 years ago
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A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper
Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

      2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}

Equation for reaction quotient is as follows.

         Q = \frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}

             = \frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}

             = 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of SO_{3} as equilibrium is achieved by using Q, is as follows.

  • This means that there are too much products.
  • Equilibrium will shift to the left towards reactants.
  • More SO_{3} is formed.
  • Partial pressure of SO_{3} increases.
4 0
3 years ago
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