Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
Yep!
Step-by-step explanation:
I'm not 100% sure if your first one is correct, but I know the second one is! Great job :)
7.5 - 3.2 = 4.3 + 4 = 8.3^3 = 571.787 ÷ 2 = 285.8935 rounded to 285.9
Exponential model because it's increasing rapidly.
