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3 years ago

If quadrilateral adqu is congruent to quadrilateral teki then quad is congruent to ____

Mathematics

1 answer:

Xelga [282]3 years ago

7 0

Answer:

KITE

Step-by-step explanation:

We are given that,

Quadrilateral ' adqu ' is congruent to quadrilateral ' teki '.

i.e. adqu ≅ teki

Now, when two figures are congruent the position of the letters are very important.

Using the positioning of the letters, we will find the quadrilateral congruent to ' quad '.

So, we see that the correspondence of letters is given by q → k, u → i, a → t and d → e.

Therefore, quad ≅ kite.

Hence, Quadrilateral ' quad ' is congruent to quadrilateral ' kite '.

You might be interested in

Can somebody please help me with this

Paul [167]

∠PYG = 137°

Step-by-step explanation:

We know that a straight line is equal to 180°, so by looking at the image we can tell that if we added both of these angles together they would be equal to the straight line.

We can make an equation by adding these two angles together and setting them equal to 180.

$2p+153+6p+91=180$

We can combine like terms.

$8p+244=180$

Subtract 244 from both sides.

$8p=-64$

Divide.

p = -8

Now that we have found what p is equal to, we can plug it in to find the measure of ∠PYG.

$2*-8+153$

= 137

If you wanted to double check this answer, we can plug in -8 for p on the other side and make sure both would be equal to 180.

Like this...

$6*-8+91$

= 43

And we know that...

137 + 43 = 180

So...

∠PYG = 137°

∠HYG = 43°

4 0

2 years ago

Evaluate: 29.04÷2.4−2.56

Crank

Answer:

9.54

Step-by-step explanation:

29.04/2.4 = 12.1

12.1-2.56 = 9.54

7 0

2 years ago

Read 2 more answers

How to order ratios least to greatest

bezimeni [28]

If you are having trouble with ratios, turn them into fractions.

ex; 3 : 5 = 3/5, 8 : 10 = 8/10, 6 : 15 = 6/15

After you have turned all of your ratios into fractions, you can find a common denominator for all the fractions.

ex; 3/5, 8/10, 6/15 ⇒ 3/5, 4/5, 2/5

Now it you can easily order the ratios from least to greatest.

ex; 6 : 15, 3 : 5, 8 : 10

8 0

2 years ago

Is 1/3, 2/3, 4/3, 8/3, 16/3 arithmetic sequence

11111nata11111 [884]

The given sequence is not arithmetic sequence

Solution:

Given sequence is:

$\frac{1}{3} , \frac{2}{3} , \frac{4}{3} , \frac{8}{3} , \frac{16}{3}$

We have to find if the above sequence is arithmetic sequence or not

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

Here in the given sequence

$\text{ first term } = a_1 = \frac{1}{3}\\\\\text{ second term } = a_2 = \frac{2}{3}\\\\\text{ third term } = a_3 = \frac{4}{3}\\\\\text{ fourth term } = a_4 = \frac{8}{3}\\\\\text{ fifth term } = a_5 = \frac{16}{3}$

Let us find the difference between terms

$a_2 - a_1 = \frac{2}{3} - \frac{1}{3} = \frac{1}{3}$

$a_3 - a_2 = \frac{4}{3} - \frac{2}{3} = \frac{2}{3}$

$a_4 - a_3 = \frac{8}{3} - \frac{4}{3} = \frac{4}{3}$

$a_5 - a_4 = \frac{16}{3} - \frac{8}{3} = \frac{8}{3}$

Thus the difference between terms is not constant

So the given sequence is not arithmetic sequence

5 0

3 years ago

For a population with an unknown distribution, the form of the sampling distribution of the sample mean is _____. Group of answe

Nesterboy [21]

For a population where the distribution is unknown, the sampling distribution of the sample mean will be b which is approximately normal for all sample sizes.

Given options regarding sample sizes.

We have to choose the correct option which shows the sample mean characteristics when the distribution is unknown.

Based on the central limit theorem the sampling distribution of the sample mean for either skewed variable ir normally distributed variable can be approximated given the mean and standard deviation.

The central limit theorem is said to be true when n greater than or equal to 30.

When n is greater than 30 ,z test is used, when n is less than 30 ,t test is used.

Hence for a population where the distribution is unknown ,the sampling distribution of the sample mean will be approximately normal for all sample sizes.

Learn more about sample at brainly.com/question/24466382

#SPJ4

Question is incomplete as it includes options in a right way:

1)exactly normal for large sample,

2) approximately normal for all sample sizes,

3) exactly normal for all sample sizes.

6 0

2 years ago