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Ipatiy [6.2K]
3 years ago
7

Which of the following choices simplified the expression:

Mathematics
2 answers:
forsale [732]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

The correct option is the second option:

\frac{5}{2},\frac{-1}{2}

<h2>Why?</h2>

We are given the following expression:

\frac{2+-\sqrt{9}}{2}

Now, solving we have:

First solution:

\frac{2+\sqrt{9}}{2}=\frac{2+3}{3}=\frac{5}{2}

Second solution:

\frac{2-\sqrt{9}}{2}=\frac{2-3}{3}=\frac{-1}{2}

Hence, we have that the correct option is the second option:

\frac{5}{2},\frac{-1}{2}

Have a nice day!

Wewaii [24]3 years ago
5 0

Answer:

The correct answer is second option

5/2, -1/2

Step-by-step explanation:

From the attached figure we can see that,

(2 ± √9 )/2

<u>To find the simplified form of (2 ± √9 )/2</u>

(2 ± √9 )/2 = (2 + √9 )/2 or (2 - √9 )/2

(2 + √9 )/2 = (2 + 3)/2 = 5/2

(2 - √9 )/2 =  (2 - 3)/2 = -1/2

Therefore simplified form of (2 ± √9 )/2 are

5/2 and -1/2

The correct answer is option 2

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Suppose a square ABCD has a side length of 1 unit. The arcs BD and AC are circular arcs with centers at A and D, respectively. F
Likurg_2 [28]

Answer:

1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}

Step-by-step explanation:

The missing figure is shown in the attachment

The area of the shaded region = Area of Square - (Area of sector AOB + Area of equilateral  triangle BOC + Area of sector COD)

Area of Sector AOB=Area of Sector COD=\frac{30}{360}*\pi*1^2=\frac{\pi}{12}

Area of equilateral triangle =\frac{1}{2}*r*\frac{\sqrt{3} }{2}*r=  \frac{1}{2}*1*\frac{\sqrt{3} }{2}*=\frac{\sqrt{3} }{4}

Area of shade region =1^2-\frac{\sqrt{3} }{4}-\frac{\pi}{12}*2

1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}

6 0
3 years ago
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Answer:

They both sold $40 worth of cookies.

Step-by-step explanation:

Using multiples the first multiple that 10 and 8 have in common is 40.

10,20,30,40

8,16,24,32,40

6 0
3 years ago
1. Which expression is equivalent to the expression below?
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Answer:

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3 years ago
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