Answer:
14800
Step-by-step explanation:
The formula for simple interest (I) in terms of principal (P), rate (R) and time (T) is given as follows;
I = P x R x T / 100 ------------- (i)
Given:
Principal (P) = Initial amount being put into the account = 10000
Rate (R) = The interest rate being offered by the account manager = 4%
Time (T) = Time taken = 12 years
Substitute these values into equation (i) as follows:
I = 10000 x 4 x 12 / 100
I = 4800
Therefore, the initial amount will yield an interest of 4800 for those 12 years.
The total amount the employee will thus have in 12 years will be the sum of the initial amount and the interest. i.e
Amount = P + I
Amount = 10000 + 4800
Amount = 14800
I think the answer would be N
You are buying 2 items so let's use two different variables to represent each:
p = number of tubes of paint
b = number of disposable brushes
cost = price per item × number of items
Equations from information given:
4p + 0.50b = 20 ← from the first 2 sentences
2p = b ← if there are twice as many brushes as paint tubes you need 2 times paint tubes to equal number of brushes
Solve the problem by using substitution... 1b equals 2p so replace b with that:
4p + 0.50(2p) = 20
4p + 1p = 20 ← 0.50 is half so half of 2p is 1p
5p = 20 ← combine like terms
p = 4 ← divide both sides of the equation by 5
Recall the equation 2p = b replace p with 4
2(4) = b
8 = b
ANSWER:
You purchased 4 tubes of paint and 8 disposable brushes.
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
