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lidiya [134]
3 years ago
5

How does osmosis help maintain body cells at a specific concentration?

Biology
2 answers:
mylen [45]3 years ago
7 0

Osmosis maintains the body cells at a specific concentration by osmoregulation.

Further Explanation:

<u>Osmosis</u> is the process of movement of water molecules from higher concentration gradient to the region where there is lower concentration gradient of water.

The water movement in or out of the cell depends on the solutions that surrounds the cell. There can be basically three types of solutions. They are:

1.<u> Hypertonic solution:</u> The solution having higher solute concentration within them. Therefore in these solution the cells shrinks as it losses water to the solution.

2. <u>Hypotonic solution:</u> The solution having lower solute concentration present in them. So the water enters into the cell leading to the swelling of the same.

3. <u>Isotonic solution:</u> when there is no net movement of the water molecules into and out of the cell.

The body cell maintains its specific concentration by the process of <u>osmoregulation</u>. The osmoregulation can be defined as the process by which the salt and water balance is maintained across the membrane within the body fluids that consists of water, electrolyte and non-electrolyte. <u>Osmotic balance</u> is controlled by both electrolyte and non-electrolyte. The body membrane is semi-permeable which allows movement of certain type of solute. The solute and water movement equalizes the solute concentration across the cell. It is taken as negative as it decreases the <u>water potential</u>.

Learn more:

1. Learn more about diffusion brainly.com/question/1233693

2. Learn more about cytoplasm brainly.com/question/1579016

3. Learn more about cell brainly.com/question/4493579

Answer Details:

Grade: College biology

Subject: Biology

Chapter:  Homeostasis

Keywords:

Osmosis, water, concentration gradient , solution, cell, hypertonic solution, hypotonic solution, isotonic solution, osmoregulation, electrolyte, non-electrolyte, semi-permeable .

givi [52]3 years ago
3 0

Osmosis is the process by which solvent molecules move through a semi permeable membrane from a region of low concentration to the region of high concentration. The movement of the solvent depend on the solute concentration at each side of the plasma membrane. In a situation, where the solute concentration on both side of the membrane is the same, then there will be no net movement of solvent across the membrane.

Body cells have specific ideal concentration levels for each ions in the cell, osmosis help to maintain this concentration by means of osmoregulation. Osmoregulation is the process by which constant osmotic pressure in the fluid content of cells is maintained by the control of salt and water concentration.

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The kinetics analyses of an enzyme are measured as a function of substrate concentration in the presence and in the absence of 2
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Answer:

take the reciprocal of the values as 1/S and 1/V and plot the values on lineweaver-burk plot.

so the re-arranged data is as following

1/S               1/V (no inhibitor)       1/V (with inhibitor)

0.333           0.096                       0.244

0.2              0.068                         0.156

0.1               0.044                         0.088

0.033          0.029                        0.044

0.011            0.024                         0.029

and the plotted lineweaver-burk plot with the equation of straight line would be....

where, first line represents the velocity of reaction with no inhibitor and second line represent the velocity in presence of inhibitor. X-axis has the substrate concentration as 1/S and y-axis has the velocity as 1/V.

as per the plot, equation of line on the lineweaver-burk plot, Y = mx + c, where c = 1/Vmax and m = Km/Vmax.

so solve for the given equations.

First, equation of line in the absence of inhibitor is Y = 0.23x + 0.021

so Vmax = 1/0.021 = 47.6 micromol/min

and Km/Vmax = 0.23, or Km = 0.23 x 47.6

Km = 10.95

Km do not have a unit, so 10.95 x 10-6 or as per your values round it up to 1 decimal point as 1.1 x 10-5

so value of Vmax = 47.6micromol/min and Km = 1.1 x 10-5 in the absence of inhibitor.

similarly, equation of line in the presence of inhibitor is given as Y = 0.67x + 0.021

so Vmax = 1/0.021 = 47.6 micromol/min

and Km/Vmax = 0.67

or Km = 0.67 x Vmax = 0.67 x 47.6 = 31.89

Km do not have a unit, so 31.89 x 10-6 or 3.1 x 10-5

so value of Vmax = 47.6micromol/min and Km = 3.1 x 10-5 in the absence of inhibitor.

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