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2 years ago

5

General admission to the Fair is $10.00. Each ride costs $4.75. If Lisa has $75.00 to spend at the Fair, what method can be used

to find out how many rides she can go on?

1 answer:

stira [4]2 years ago

4 0

Answer:

subtraction

Step-by-step explanation:

:)

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Need help. greatly appreciated

gizmo_the_mogwai [7]

1. It must be divisible by 2 and 3. It IS divisible by 2. it IS divisible by 3. No remainder.
2. Add the digits and see if the sum is divisible by 3. Apply this rule to both numbers. 3 is not a common factor.
3a. 639
3b. 1035
3c. 179

7 0

2 years ago

HURRY UP I NEED THE ANSWER

vladimir1956 [14]

Answer:

g(2) = 2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that $g(x) = \frac{-1}{2} x + 3$

Put x =2

$g(2) = \frac{-1}{2} (2) + 3$

= -1+3

= 2

g(2) = 2

5 0

2 years ago

A number is divided by 3 and decreased by 5 is 6. What is the number???

KATRIN_1 [288]

Answer:

Given : x/3-5=6

answer = 23

Step-by-step explanation:

x-5=6*3

x-5=18

x=18+5

x=23

7 0

2 years ago

Read 2 more answers

4/5+ 1/3 how much is it

Andreas93 [3]

4/5 = 12/15
1/3 = 5/15
17/15 = 1 2/15

4 0

2 years ago

4tan^2 x-8tanx+3=0 on interval [0,2pi]

Vadim26 [7]

$\bf 4tan^2(x)+8tan(x)+3=0\qquad [0,2\pi ]
\\\\\\
\textit{since it's just a quadratic, we'll just factor it}
\\\\\\\
[2tan(x)+1][2tan(x)+3]=0\implies 
\begin{cases}
2tan(x)+1=0\\
\qquad tan(x)=-\frac{1}{2}\\
\qquad \measuredangle x=tan^{-1}\left( -\frac{1}{2} \right)\\
\qquad \measuredangle x\approx 333.4^o, 153.4^o\\
2tan(x)+3=0\\
\qquad tan(x)=-\frac{3}{2}\\
\qquad \measuredangle x=tan^{-1}\left(-\frac{3}{2} \right)\\
\qquad \measuredangle x\approx303.7^o, 123.7^o
\end{cases}$

7 0

2 years ago