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Fynjy0 [20]
3 years ago
10

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are m= 1.0\ kg

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

  • Let initial velocity of ball A\ is\ u_1
  • Initial velocity of ball B\ is\ u_2
  • Final velocity of ball A\ is\ v_1
  • Final velocity of ball B\ is\ v_2
  • Momentum before collision = mu_1+mu_2
  • Momentum after collision =mv_1+mv_2

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

mu_1+mu_2=mv_1+mv_2

We will plug each trial to this equation.

Trial 1

mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3

Trial 2

mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1

Trial 3

mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1

Trial 4

mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

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