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spin [16.1K]
3 years ago
13

What is the simplified form of the quantity of x plus 7, all over the quantity of 6 − the quantity of x plus 5, all over the qua

ntity of x plus 3? (2 points) Question 4 options: 1) the quantity of x squared plus 16x plus 51, all over 6 times the quantity of x plus 3 2) the quantity of x plus 2, all over the quantity of 3 minus x 3) the quantity of x squared plus 4x minus 9, all over 6 times the quantity of x plus 3 4) the quantity of 2, all over the quantity of 3 minus x
Mathematics
1 answer:
vlabodo [156]3 years ago
5 0

For this case we must simplify the following expression:

\frac {\frac {x + 7} {6- (x + 5)}} {x + 3}

We must apply double C:

\frac {(x + 7) (x + 3)} {6- (x + 5)} =

We apply distributive property in the numerator:

\frac {x ^ 2 + 3x + 7x + 21} {6- (x + 5)} =\\\frac {x ^ 2 + 10x + 21} {6- (x + 5)} =

In the denominator we have by law of signs:

- * + = -\\\frac {x ^ 2 + 10x + 21} {6-x-5} =

Different signs are subtracted and the sign of the major is placed:

\frac {x ^ 2 + 10x + 21} {- x + 1}

ANswer:

\frac {x ^ 2 + 10x + 21} {- x + 1}

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kiruha [24]

Answer: (1st box) = 6 (2nd box) = 2 (3rd box) = 2/3

Step-by-step explanation:

4 0
4 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
A retailer (GameStop, Target, or other stores) will receive 23% of the sale price of a video game. If a retailer sells a video g
prohojiy [21]

Answer:

$13.80

Step-by-step explanation:

23% of 60 = .23 x 60

5 0
3 years ago
Factoring polynomial and expanding
Vlada [557]
I would say 112x + 128x
5 0
4 years ago
anna owes home antiques Whose value is 160000 today assuming normal growth. however anna believes the value will grow at 16% per
Ray Of Light [21]
The formula is
A=p (1+r)^t
A future value?
P present value 160000
R interest rate 0.16
T time 3years
A=160,000×(1+0.16)^(3)
A=249,743.36

Use that future value to find the present value at a rate 8% compounded annually
To find p (present value) solve the formula for p
P=A÷ (1+r)^t
Where r is 0.08
P=249,743.36÷(1+0.08)^(3)
p=198,254.33
3 0
3 years ago
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