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aleksandr82 [10.1K]
3 years ago
8

3x + 3 = x - 5 Solve for x

Mathematics
2 answers:
OLga [1]3 years ago
7 0
Answer:
-4
Explanation:
3(-4)+3=-4-5
^ ^
-12 -9
-12+3=-9
^
-9 =-9
Mars2501 [29]3 years ago
4 0

Answer:

x = -4

Step-by-step explanation:

plz vote brainliest :)

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slega [8]

Answer:

1) Reflection in the x-axis

A' = (-2, -3)

2) Rotation of 180° clockwise about the origin

A'' = (2, 3)

3) Translation of 3 units down and 4 units to the right

A''' = (6, 0)

Step-by-step explanation:

The transformations are as follows;

1) Reflection in the x-axis

Here the x-coordinate is the same and the y-coordinate changes sign.

Therefore, we have;

A (-2, 3)

After reflection in the x-axis becomes A' = (-2, -3)

2) Rotation of 180° clockwise about the origin

When, a point (x, y) is rotated 180° clockwise about the origin, it becomes (-x, -y)

Therefore, we have;

A' = (-2, -3) becomes A'' = (2, 3)

3) Translation of 3 units down and 4 units to the right

Translation of 3 units down and 4 units to the right = T_{(4, -3)

Which gives

A''' = (2 + 4, 3 - 3) = (6, 0).

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An equation was used to predict possible weights of puppies at 6 months of age. The actual weights of the puppies are also liste
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A recipe calls for 4 carrots for every 2 cups of water. Which expression can be used to find the number of carrots needed for 1
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The operating costs for each machine for one day have an unknown distribution with mean 1610 and standard deviation 136 dollars.
Lelechka [254]

Answer:

The standard deviation for the sample mean distribution is \sigma_{\bar{X}}=\frac{136}{\sqrt{45}}=\frac{136\sqrt{5}}{15} \approx 20.274

Step-by-step explanation:

The central limit theorem states that if you have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population then the distribution of the sample means will be approximately normally distributed.

For the random samples we take from the population, we can compute the standard deviation of the sample means:

\sigma_{\bar{X}}=\frac{\sigma}{\sqrt{n}}

From the information given

The standard deviation σ = 136 dollars

The sample n = 45

Thus,

\sigma_{\bar{X}}=\frac{136}{\sqrt{45}}=\frac{136\sqrt{5}}{15} \approx 20.274

The standard deviation for the sample mean distribution is \sigma_{\bar{X}}=\frac{136}{\sqrt{45}}=\frac{136\sqrt{5}}{15} \approx 20.274

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4 years ago
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