Question

(-y^5)(8y^2) and (-7^5)(9y) and (-7^5)(-5)

Answer 1

Answer:

$-8y^{25}\\-9y^6\\5y^5$

Step-by-step explanation:

First one.

$((-y)^5)(8y^{20})=-y^5*8y^{20}=-8y^{5+20}=-8y^{25}$

Second one

$((-y)^{5} )(9y)=-y^5*9y=-9y^{5+1}=-9y^6$

and last one

$((-y)^5)(-5)=-y^5*(-5)=5y^5$