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inessss [21]
3 years ago
15

Lucy throws a fair six sided dice . so like the letter that matches the probability of the dice landing on a number between 1 an

d 6.
(diagram in the image attached.)​

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

Letter B matches the probability.

Step-by-step explanation:

Lucy throws a fair six sided dice.

Probability of the dice landing on a number between 1 and 6 = \frac{\text{Favorable outcome}}{\text{Number of events}}

= \frac{1}{6}

On a number line fraction \frac{1}{6} can be represented by,

An small section (A to B) will represent the fraction = \frac{1}{6}

Therefore, letter B will match the probability of a dice landing on a number between 1 and 6.

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Maurinko [17]

Answer:

616 square centimeters

Step-by-step explanation:

Area of a circle is equal to pi × r^2. In this case, they have asked that you substitute 3.14 or 22/7 for pi, so I will be using 22/7, instead.

Diameter is equal to 2r; to find the radius, simply divide 28 by two. This gives us a radius of 14.

Multiply 14 squared by 22/7:

(22/7)(14^2)

This gives us (22/7)(196); (4312/7); 616.

Therefore, the area of the circle is approximately 616 square centimeters.

8 0
2 years ago
Find the missing value.-7/13 = m/104
exis [7]

<em>answer = - 56  \\ solution \\  \frac{ - 7}{13}  =  \frac{m}{104}  \\ or \: 13 \times m = 104 \times ( - 7) \\ or \: 13 \: m =  - 728 \\ or \: m =  \frac{ - 728}{13}  \\ m = -  56 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

8 0
3 years ago
Read 2 more answers
If g(x) = 2x + 1 and fog (x)=6x-2, find f(x).​
Nostrana [21]

Answer:

g(x) = f(x) \\ 2x + 1 = 6x - 2 \\ 2x - 6x =  - 2 - 1 \\  - 4x =  - 3 \\ x =  \frac{3}{4}

6 0
2 years ago
Read 2 more answers
g If a hypothesis test with a significance level of α rejects H0: μ1=μ2 in favor of Ha: μ1≠μ2, then thecorresponding (1- α)% con
Effectus [21]

Answer:

The statement, (1- <em>α</em>)% confidence interval for (μ₁ - μ₂) does not contain zero is TRUE.

Step-by-step explanation:

The hypothesis for a test is defined as follows:

<em>H</em>₀: μ₁ = μ₂ vs. <em>H</em>ₐ: μ₁ ≠ μ₂

It is provided that the test was rejected st the significance level <em>α</em>%.

If a decision is to made using the confidence interval the conditions are:

If the null hypothesis value is not included in the (1 - <em>α</em>)% confidence interval then the null hypothesis will be rejected and vice versa.

In this case the null hypothesis value is:

<em>H</em>₀: μ₁ - μ₂ = 0.

If the value 0 is not included in the (1 - <em>α</em>)% confidence interval for the difference between two means, then the null hypothesis will be rejected.

Thus the statement, (1- <em>α</em>)% confidence interval for (μ1- μ2) does not contain zero is TRUE.

5 0
3 years ago
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
salantis [7]
The formula for the average value of a function is \frac{1}{b-a}  \int\limits^b_a {f(x)} \, dx where b is the upper bound and a is the lower.  For us, this formula will be filled in accordingly.  \frac{1}{2}  \int\limits^2_0 {(2x^2+3)} \, dx.  We will integrate that now: \frac{1}{2}[ \frac{2x^3}{3}+3x] from 0 to 2.  Filling in our upper and lower bounds we have \frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0] which simplifies to \frac{1}{2}( \frac{16}{3}+6) and \frac{1}{2}( \frac{16}{3}+ \frac{18}{3})= \frac{1}{2}( \frac{34}{3}) which is 17/3 or 5.667
7 0
3 years ago
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