The area of the square pyramid building is the amount of space on it
The maximum base length of the building is 67.42 cm
<h3>How to determine the maximum side length?</h3>
The given parameters are:
Base = b
Slant height (l) = 5b
The lateral surface area is calculated using:
L = 2bl
So, we have:
L = 2 * b * 5b
Evaluate the product
L = 10b^2
The total surface area is calculated using:
T = L + b^2
So, we have:
T = 10b^2 + b^2
Evaluate the sum
T = 11b^2
The maximum surface area is 50,000 square feet
So, we have:
11b^2 = 50000
Divide both sides by 11
b^2 = 50000/11
Take the square root of both sides
b = 67.42
Hence, the maximum base length of the building is 67.42 cm
Read more about square pyramids at:
brainly.com/question/27226486
→ Solutions
⇒ Simplify <span><span><span>4<span>(<span>2a</span>)</span></span>+<span>7<span>(<span>−<span>4b</span></span>)</span></span></span>+<span><span>3c</span><span>(5)</span></span></span><span>⇒ </span><span><span><span><span><span>8a</span>+</span>−<span>28b</span></span>+<span>15<span>c
Answer
</span></span></span></span><span>⇒ </span><span>8a−28b</span><span>+</span><span>15c</span>
Answer:
8,920 ÷ 80=111.5
892 ÷ 8=111.5
89.2 ÷ 0.08=111.5
.892 ÷ 0.008=111.5
Step-by-step explanation:
Answer:
Midpoint (-2,4)
distance nearest tenth = 8.9
The approximate distance = 9
Step-by-step explanation:
Formulas
PQ midpoint = (x2 + x1)/2, (y2 + y1)/2
distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
Givens
x2 = -4
x1 = 0
y2 = 1
y1 = 7
Solution
M(PQ) = (-4+0)/2, (1 + 7)/2
M(PQ) = -2, 4
The midpoint is -2,4
The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )
The distance = sqrt(16 + 64)
The distance = sqrt(80)
The distance = 4√5 exactly
The distance = 8.94
The distance = 8.9 To the nearest tenth
Question 2
The distance is rounded to the nearest whole number which is 9.
Answer:
b
Step-by-step explanation:
because we can not some times change the places in addition so b is the correct answer
