Which of the following best explains why a structural formula of a chemical compound is more useful than a molecular formula?

2 answers:

7 0

The answer is A) Both formulas identify the specific in a particular compound. However, a <span>structural formula also shows how the atoms in a compound are bonded together.

Molecular formula:
Advantage: shows chemical composition
Disadvantage: No structural information

Structural formula:
Advantage: shows chemical connectivity
Disadvantage: Minimal three dimensional

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Ganezh [65]3 years ago

5 0

Answer: the correct answer is (A).

Explanation:

Structural formula not only tells us about the number and types of atoms in a molecule but also tells us about the bonded positions of all the atoms in a molecule of that particular compound.

Molecular structure only tells us about the numbers of atoms and types of atoms present in a molecule of that particular compound.

For example: Molecular formula of propanone and propanal are same that is $C_3H_6O$ but structural formula is different that $CH_3COCH_3$ for propane and $CH_3CH_2CHO$ for propanal. Here structural formula is showing that how the atoms in propanone and propanal are bonded together.

Hence, the correct answer is option (A).

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Draw the alkene formed when 1-heptyne is treated with hbr in the presence of peroxide.

Nimfa-mama [501]

<h2>Heptene formed is -</h2><h2> $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$ </h2>

Explanation:

The two possibilities when the peroxide is not present

$CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-C$ ≡ $CH +HBr$ → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_{2}$

$CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_2$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr_2-CH_3$

In presence peroxide,

$CH_3-CH_2-CH_2-CH_2-CH_2-C$ ≡ $CH$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

When peroxides are present in the reaction mixture, hydrogen bromide adds to the triple bond of heptane with regioselectivity.

This reaction is opposite to that of Markovnikov's rule which says that when asymmetrical alkene reacts with a protic acid HX, then the hydrogen of an acid is attached to the carbon with more in number of hydrogen substituents, and the halide (X) group is attached to the carbon with more in number of substituents of alkyl.
One mole of HBr adds to one mole of 1-heptane.
The structure of heptene formed is -

$CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

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