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DaniilM [7]
3 years ago
5

If 80 joules of work were necessary to move a 5 newton box, how far was the box moved?

Physics
1 answer:
klemol [59]3 years ago
3 0

Explanation:

work=force/distance

work=80

force=5

putting value of force and work we get

80=5/distance

5/80=distance

1/16=distance

or

0.0625m

6.25cm

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A resistor R and a capacitor C are connected in series to a battery of terminal voltage V0. Which of the following equations rel
Lesechka [4]
Answer-C VO2-Q2/2C-I2R=0
Q1/2C currents upon the charge I2R on the capacitor. Voltage V02 goes best
5 0
3 years ago
A 42.0-cm diameter disk rotates with a constant angular acceleration of 2.70 rad/s2. It starts from rest at t = 0, and a line dr
Zielflug [23.3K]

Answer:

6.21 rad/s

1.3041 m/s, 0.567 m/s²

106.4778\ ^{\circ}

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity = 0

\alpha = Angular acceleration = 2.3 rad/s²

\theta = Angle of rotation

t = Time taken = 2.3 s

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=0+2.7\times 2.3\\\Rightarrow \omega_f=6.21\ rad/s

The angular speed is 6.21 rad/s

Linear velocity is given by

v=r\omega\\\Rightarrow v=0.21\times 6.21\\\Rightarrow v=1.3041\ m/s

Linear velocity is 1.3041 m/s

Tangential acceleration is given by

a_t=r\alpha\\\Rightarrow a_t=0.21\times 2.7\\\Rightarrow a_t=0.567\ m/s^2

Tangential acceleration is 0.567 m/s²

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2.7\times 2.3^2\\\Rightarrow \theta=7.1415\ rad

In degress the angle would be

57.3+7.1415\times \dfrac{180}{\pi}=466.47780\ ^{\circ}

From x axis it would be

466.47780-360=106.4778\ ^{\circ}

The angle is 106.4778\ ^{\circ} from x axis

7 0
4 years ago
La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el p
liubo4ka [24]

Answer:

11025 N / m²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Área (A) = 400 cm²

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Presión (P) =?

A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Fuerza (F) =.?

F = m × g

F = 45 × 9,8

F = 441 N

A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:

1 cm² = 0,0001 m²

Por lo tanto,

400 cm² = 400 cm² × 0,0001 m² / 1 cm²

400 cm² = 0,04 m²

Por tanto, 400 cm² equivalen a 0,04 m².

Finalmente, determinaremos la presión ejercida de la siguiente manera:

Área (A) = 0.04 m².

Fuerza (F) = 441 N

Presión (P) =?

P = F / A

P = 441 / 0,04

P = 11025 N / m²

Por tanto, la presión ejercida es 11025 M / m²

4 0
3 years ago
Which measurement tool is used to find the volume of a small piece of granite? Select one: a. thermometer b. metric ruler c. gra
Natalka [10]

Answer:

Explanation:

c. graduated cylinder

3 0
3 years ago
How can density be determined in a lab of a rectangular solid?
True [87]
We will first record its mass and then its volume by measuring its dimensions
then divide mass by volume and will get density of regular solid
6 0
3 years ago
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