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3 years ago

The early experiments with static charges were done by:

Physics

1 answer:

Naddika [18.5K]3 years ago

5 0

Answer:

the answer is b .Gilbert

Explanation:

hope it helps !

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Much of the energy of falling water in a waterfall is converted into heat. If all the mechanical energy is converted into heat t

Assoli18 [71]

Answer:

Explanation:

potential energy of water is converted into heat energy

P E = mgh = m x 9.8 x 111

= 1087.8 m .

Let rise in temperature θ

m x s x θ = heat absorbed

m x s x θ = 1087.8 m

m x 4182 x θ = 1087.8 m

θ = 0.26 degree celsius .

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3 years ago

What are two ways you could alter the design of a baseball to make it travel faster from the pitcher's mound to home plate? Expl

Harrizon [31]

Make it weigh less. Make it smaller

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3 years ago

Read 2 more answers

A china dish falls from a height of 1.5 m above the floor. Calculate its velocity just before it

alexandr402 [8]

Answer:

12m/s

Explanation:

v^2=u^2+2as

v=?

u=0 (the dish was stationary before it fell)

a=9.81 m/s^2 (acceleration due to gravity/freefall)

s=1.5m (the drop height)

So: v^2=0+2.9.81.1.5 = 144.35415

and therefore v=sqrt 144.35415

12x12=144 so I'd say v=12m/s

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3 years ago

If jack was traveling at 100 miles in 2 hours what was his speed in miles per minute?

aniked [119]

50 mph

100 divided by 2

4 0

3 years ago

PLEASE HELP ME ASAP

Ann [662]

Answer:

1. Current in the circuit; 1.2 Amps

See attached image for the circuit.

2. Equivalent resistor = 3 Ω

I = 0.3 amps

Potential difference across the battery terminals is: 0.9 V

Explanation:

Part 1.

The internal resistance of 2 ohms is simply added to the circuit in series as shown in the attached image.

Since now we have two resistances in series (2 ohms and 3 ohms) the total of this series combination is 5 ohms. Using Ohm's law, we can derive the current running through the circuit:

$V=I\,\,R\\6\,V=I\,(5\,\Omega)\\I=\frac{6}{5} \,amps\\I=1.2\,\,amps$

Part 2.

Now we have a 1.5 V battery with a 2 ohm internal resistance, connected to two identical 6 ohm resistors.

a. The equivalent resistance presented by the two resistors in parallel:

$\frac{i}{R_e} =\frac{1}{6\,\Omega} + \frac{1}{6\,\Omega} =\frac{1}{3\,\Omega} \\R_e=3\,\Omega$

b. Now the circuit can be represented by a 2 ohm resistor (internal battery resistance) plus a 3 ohm parallel equivalent resistor in series. That is a 5 ohm total resistance. Then Ohm's law becomes:

$V=I\,\,R\\1.5\,V=I\,(5\,\Omega)\\I=\frac{1.5}{5} \,amps\\I=0.3\,\,amps$

c. The potential difference across the battery terminals must be the battery's EMF minus the potential drop in its internal resistance:

$1.5\,V - (0.3\,\,amps)\,(2\,\Omega)=(1.5-0.6)\,V=0.9\,V$

6 0

3 years ago