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meriva
3 years ago
6

Please help! Image Below!

Mathematics
2 answers:
sattari [20]3 years ago
7 0
The answer is C I took the test before hopes it helps(:
drek231 [11]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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4 value of 546 210 in words
FrozenT [24]
Five hinder and fourty six and two hundred and ten
3 0
2 years ago
Write the pair of fractions as a pair of fractions with common denominators 2/12 and 4/6
lukranit [14]

Answer: 1/6

Step-by-step explanation:

just simplify 2/12 to 1/6

2/12 both divided by 2

4 0
2 years ago
a radio station had 234 tickets to a concert. They gave away 5 times as many tickets to listeners as to employees. how many tick
RSB [31]

Answer:

39 tickets were given to the employees

Step-by-step explanation:

1. Approach

First, list the given information, then form an equation based on the given information. Finally, solve the equation with simplification and inverse operations.

2.Given

A total of 234 tickets were given away

5 times as many tickets were given away to listeners compared to employees

-Call the number of tickets given away to employees (x)

3. Form an equation

(Tickets_given_to_employees) + (Tickets_given_to_listeners) = (Total_tickets)

Substitute,

x + 5x = 234

Simplify,

6x + 234

Inverse operations,

6x = 234

/6      /6

x = 39

5 0
3 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
1 year ago
WILLL GIVE BRAINLIEST + 50 POINTS FOR HELP!!!!<br><br><br>PLZZZZZZ IM TIMED
andrew-mc [135]
First. y=2x
second d is correct
third is a
7 0
2 years ago
Read 2 more answers
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