Question

A 33 gram sample of a substance that's

Answer 1

9514 1404 393

Answer:

  6.2

Step-by-step explanation:

We presume your "k-value" is the k in the exponential decay term ...

  e^(-kt) . . . where t is the number of time units

This is 1/2 when ...

  ln(1/2) = -kt

  t = ln(1/2)/(-k) = ln(2)/k

  t = 0.69315/0.1124 ≈ 6.2

The half life is about 6.2 time units.