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Yakvenalex [24]
3 years ago
15

The expression log1/3/log2 is the result of applying the change of base formula to a logarithmic expression. Which could be the

original expression? ​

Mathematics
2 answers:
nasty-shy [4]3 years ago
7 0

Answer:

C

Step-by-step explanation:

given log_{b} a, then the change of base is

\frac{loga}{logb}

For the given expression a = \frac{1}{3} and b = 2, hence

The original expression is therefore

log_{2} \frac{1}{3} → C

Dovator [93]3 years ago
5 0

Answer:

Option C. log_{2}\frac{1}{3}

Step-by-step explanation:

The given logarithmic expression is \frac{log(\frac{1}{3} )}{log2}

Rule of logarithm says

\frac{log_{e}a }{log_{e}b}=log_{b}a

So by this rule,

expression \frac{log(\frac{1}{3} )}{log2} will become log_{2}\frac{1}{3}

Therefore, Option C. log_{2}\frac{1}{3} will be the answer.

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In a random sample of 400 residents of Boston, 320 residents indicated that they voted for Obama in the last presidential electi
coldgirl [10]

Answer:

C.I =  0.7608   ≤ p ≤   0.8392

Step-by-step explanation:

Given that:

Let consider a  random sample n = 400 candidates where  320 residents indicated that they voted for Obama

probability \hat p = \dfrac{320}{400}

= 0.8

Level of significance ∝ = 100 -95%

= 5%

= 0.05

The objective is to  develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

The confidence internal can be computed as:

=\hat p  \pm Z_{\alpha/2} \sqrt{\dfrac{ p(1-p)}{n } }

where;

Z_{0.05/2} = Z_{0.025} = 1.960

SO;

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(1-0.8)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.8(0.2)}{400 } }

=0.8  \pm 1.960 \sqrt{\dfrac{ 0.16}{400 } }

=0.8  \pm 1.960 \sqrt{4 \times 10^{-4}}

=0.8  \pm 1.960 \times 0.02}

=0.8  \pm 0.0392

= 0.8 - 0.0392     OR   0.8 + 0.0392  

= 0.7608    OR    0.8392

Thus; C.I =  0.7608   ≤ p ≤   0.8392

3 0
2 years ago
NECESITO AYUDA EN ESTOS EJERCIICIOS DE MATES NIVEL SEGUNDO ESO
Kay [80]

Answer: 49/60

Step-by-step explanation:

(1/3+2/5)-1/4-(5/6-7/6)

Primero  (5/6-7/6)

5/6-7/6=-2/6

1/3+2/5-1/4-(-2/6)

1/3+2/5-1/4+2/6

2/6=1/3

1/3+2/5-1/4+1/3

2/3+2/5-1/4

2/3=10/15

2/5=6/15

10/15+6/15-1/4

16/15-1/4

16/15=64/60

1/4=15/60

64/60-15/60=49/60

4 0
3 years ago
PLEASE ANSWERRRRRRRRRR
mash [69]

Answer: OPTION B.

Step-by-step explanation:

Given the following System of equations:

\left \{ {{3x-5y=19} \atop {x+y=1}} \right.

You can use the Elimination Method to solve it. The steps are:

1. You can mutliply the second equation by -3.

2. Then you must add the equations.

3. Solve for the variable "y".

Then:

\left \{ {{3x-5y=19} \atop {-3x-3y=-3}} \right.\\.....................\\-8y=16\\\\y=\frac{16}{-8}\\\\y=-2

4. Now that you know the value of the variable "y", you must substitute it into any original equation.

5. The final step is to solve for "x" in order to find its value.

Then:

x+(-2)=1\\\\x=1+2\\\\x=3

Therefore, the solution is:

(3,-2)

8 0
3 years ago
Can anyone help me on this and pls explain this
7nadin3 [17]
I can’t really see it well
3 0
3 years ago
Some sales positions pay a commission if sales exceed a set quota. Yolanda Gonzalez is paid $2,000 per month plus a commission o
max2010maxim [7]
It would be $2000 for that month.
4 0
3 years ago
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