What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
x = 20.75
Step-by-step explanation:
<u>Step 1: Solve for x</u>
4x + (-9) = 74
4x - 9 + 9 = 74 + 9
4x / 4 = 83 / 4
x = 20.75
Answer: x = 20.75
Answer: We should reject the null if the test statistic is greater than <u>1.895</u>.
Step-by-step explanation:
We assume the population to be normally distributed.
Given: Sample size :
, which is asmall sample (n<30), so we use t-test.
We always reject the null hypothesis if the absolute t-value is greater than critical value.
Therefore, We should reject the null if the test statistic is greater than <u>1.895</u>.
The correct answer is :

Just it....
And we're done.
Thanks for watching buddy good luck.
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Answer:
I think it -1.50 to 10.58
Step-by-step explanation: