Answer:
Step-by-step explanation:
If the profit realized by the company is modelled by the equation
P (x) = −0.5x² + 120x + 2000, marginal profit occurs at dP/dx = 0
dP/dx = -x+120
P'(x) = -x+120
Company's marginal profit at the $100,000 advertising level will be expressed as;
P '(100) = -100+120
P'(100) = 20
Marginal profit at the $100,000 advertising level is $20,000
Company's marginal profit at the $140,000 advertising level will be expressed as;
P '(140) = -140+120
P'(140) = -20
Marginal profit at the $140,000 advertising level is $-20,000
<u>Based on the marginal profit at both advertising level, I will recommend the advertising expenditure when profit between $0 and $119 is made. At any marginal profit from $120 and above, it is not advisable for the company to advertise because they will fall into a negative marginal profit which is invariably a loss.</u>
Answer:
percent* base = amount
.2 * x = 1.80
x = 1.80/.2
x= $9
Step-by-step explanation:
Answer:
Before coming back up to the surface the maximum depth, Cassidy went was 6.25 ft. below the water surface
Step-by-step explanation:
The height of Cassidy's diving platform above the water = 6 ft.
The equation that models her dive is d = x² - 7·x + 6
Where;
d = Her vertical position or distance from the water surface
x = Here horizontal distance from the platform
At Cassidy's maximum depth, we have;
dd/dx = d(x² - 7·x + 6)/dx = 2·x - 7 = 0
x = 7/2 = 3.5
∴ At Cassidy's maximum depth, x = 3.5 ft.
The maximum depth, 
= d(3.5) = 3.5² - 7 × 3.5 + 6 = -6.25
The maximum depth, Cassidy went before coming back up to the surface = = -6.25 ft = 6.25 ft. below the surface of the water.
