The width of the walkway is 8m
Step-by-step explanation:
Given that,
Dimensions of pool is 22 x 10
The area of the pool including the walkway = 540 sq. meter
The area of the pool = 22 x 10
= 220 sq. meter
The area of the walkway= 540 - 220
= 320 sq. meter
The area of the pool with the walkway= 540 sq. meter
Let the width of the walkway be 'w'
Area = (22+w) (10+w)
540 = 220+22w+10w+(w^2)
540-220 = 32w + (w^2)
320 = (w^2) + 32w
(w^2) +32w = 320
(w^2) +32w - 320 = 0
Solving the quadratic equation by splitting the middle term.
(w^2) +40w -8w -320 =0
w(w+40) -8(w+40) =0
(w+40) (w-8) =0
w= 8 (or) -40
The width cannot be negative so the width of the walkway is 8 meter
I would say A. 3(x + 7) = 6. x is the number chosen, and it would be added to 7, so you get x + 7. The sum is then multiplied by 3, so you would put 3 on the outside of the parenthesis, as you always do parenthesis first. Going along with Pemdas-Parenthesis first (or Gemdas-grouping symbols first). Hope this helps!
He'd end up where he started
Any number subtracted from the same number = 0
If you add the same number twice, and then remove it from it twice, it will also equal 0.
5 + 5 = 10
10 - 5 = 5 - 5 = 0
5 - 5 = 0
The Answer For This Is 5^3<span>√10 - 1/2</span>
Answer:
p=.84
Step-by-step explanation:
p=8.94/3=3.82
p+2.98=3.82
p=.84