R(x) = 20x 0,004x² = C(x)800+ 2x + 0.001x²
1 answer:
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To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides
1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself
Every week he withdraws $35 from the $950 in his savings, and he wants at least $600 by the end of the summer. So we could write:
Where 'x' is the number of weeks. Now let's solve it for 'x'.
Subtract 950 to both sides:
Divide -35 to both sides, don't forget to switch the sign when dividing/multiplying by a negative number:
So he can only withdraw at money for at most 10 weeks if he wants at least $600 left in his account.
Where 'x' is the number of weeks. Now let's solve it for 'x'.
Subtract 950 to both sides:
Divide -35 to both sides, don't forget to switch the sign when dividing/multiplying by a negative number:
So he can only withdraw at money for at most 10 weeks if he wants at least $600 left in his account.