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3 years ago

Given fx) = 17- x2, what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics

2 answers:

Andrei [34K]3 years ago

6 0

Let [a, b] = the interval

The average rate of change can be found by using [f(b) - f(a)]/(b - a).

Let a = 1 and b = 5.

Let R = rate of change

17- x^2

R = [17 - 5^2] - [17 - 1^2]/(5 - 1)

R = [17 - 25] -[17 - 1]/4

R = [(-8) - (16)]/4

R = (-24)/4

R = -6

Done.

vredina [299]3 years ago

6 0

Answer: A. -6

Step-by-step explanation:

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In the figure below, segment AC is congruent to segment AB.

jeyben [28]

<span>Triangle ACD is similar to triangle ABD</span>

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3 years ago

Phyllis invested 50000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7

Elodia [21]

Answer:

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

Let

x-----> the amount invested at 5%

50,000-x -----> the amount invested at 7%

$t=1\ year\\ I=\$2,720\\r_1=0.05\\r_2=0.07\\P_1=\$x\\P_2=\$(50,000-x)$

substitute in the formula above

$2,720=x(0.05*1)+(50,000-x)(0.07*1)$

solve for x

$2,720=0.05x+3,500-0.07x$

$0.07x-0.05x=3,500-2,720\\0.02x=780\\x=\$39,000$

$(50,000-x)=\$11,000$

therefore

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

5 0

4 years ago

G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1

Paladinen [302]

Answer:

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent the possible outcome of rolling the two die

Then the total number of possibilities for the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of fair dice.

Therefore, Probability(1) = 0

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4 years ago

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2 years ago

Which linear equation has no solution? 5x+12=5x−7

soldier1979 [14.2K]

Answer:

Trying to solve this leads to an absurdity, so No Solution.

Step-by-step explanation:

5x+12=5x−7

Lets attempt to solve:

Subtract 5x from both sides

5x - 5x + 12 = 5x - 5x - 7

0 + 12 = 0 - 7

12 = -7

This is absurd so there is no solution.

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3 years ago