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3 years ago

Given fx) = 17- x2, what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics

2 answers:

Andrei [34K]3 years ago

6 0

Let [a, b] = the interval

The average rate of change can be found by using [f(b) - f(a)]/(b - a).

Let a = 1 and b = 5.

Let R = rate of change

17- x^2

R = [17 - 5^2] - [17 - 1^2]/(5 - 1)

R = [17 - 25] -[17 - 1]/4

R = [(-8) - (16)]/4

R = (-24)/4

R = -6

Done.

vredina [299]3 years ago

6 0

Answer: A. -6

Step-by-step explanation:

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e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

$\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1$

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

$\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}$

STEP 3: Get the equation of the ellipse

$\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}$

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

$\frac{x^2}{144}+\frac{y^2}{95}=1$

OPTION A

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