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katovenus [111]
3 years ago
11

Mobile phones that function as credit cards are called _____.

Computers and Technology
1 answer:
11111nata11111 [884]3 years ago
7 0
The answer is A- Mobile Wallet
It can be used to pay for your purchases instead of using your actual card. It may be an app or it may be already built into the device. It is actually more convenient to others because you can just hold your device at the terminal when you will pay. Mobile Wallets may be smartphones or tablets.
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Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
If a friend changes the password on your phone how do you get into it if you dont know the password
kotegsom [21]
Ask your friend to tell you the password
3 0
3 years ago
Displays information a bout drivers, network connections, and other program-related details.
slava [35]

Answer:

library

Explanation:

hope you like it

6 0
3 years ago
Write a function file that accepts the values of r, a and n as arguments and uses a for loop to return the sum of the first n te
Murrr4er [49]

Given, a = 3, r = 1/2, n = 10

%r is common ratio

%n is number of terms

%a is the first term of the series

Sum = 0;

a = 3;

r = 1/2;

for i = 0 : 1 :  10;

Sum = Sum + a * r ^ i;

end

Sum


7 0
3 years ago
Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value is consi
Darya [45]

// Variable to keep track of array size

int length = 0;

// Array itself

int array[] = {};

// while loop will take input in the array until a negative number is entered

while(input>=0){

stdin = new Scanner(System.in);

array[length] = stdin;

length +=1;

}

// int variable to terminate while loop

int i =0;

// keep track of index of output array

int y =0;

while(arr[i] != length){

// making output array

int output[]={}; bool flag;

// put the element in out put array considering if it the desired one

output[y] = array [i];

// Now check if it was the desired?

for(int z=1;z<=length;z++){

if(array[i+z]!=output[y]){

 flag = true;

}

else

{

 output[y]=0;

 y+=1;

}

if(array[i+z+1]=output[y] && flag == true){

output[y] = array[i];

y+=1;

}

}

//output the array

for(int o=0;o<y;o++)

System.out.println(output[o];

3 0
3 years ago
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