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Otrada [13]
3 years ago
6

Jenny is a 60% free-throw shooter. She gets to shoot a second free throw if and only if she makes her first shot. She can score

0 points (if she misses her first shot), 1 point (she makes her first but misses her second), or 2 points (she makes both shots).
Suppose Jenny gains confidence after making her first free throw and the probability of her making the second free throw goes up to 70%. Now, what number of points is Jenny most likely to make when she shoots a one-and-one?
Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

hi

Step-by-step explanation:

Andrew [12]3 years ago
3 0
If the probability of each of her shots going in is higher than 50% then the highest probability scenario is that she scores both
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Answer:

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-3 + 28n \geq  -32\\+3                      +3\\28n  \geq  -29\\/28              /28\\n \geq \frac{-29}{28}

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nadya68 [22]

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6.4

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ik it doesnt make any sinse but hope this helps

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When AB = 5.2:

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