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Otrada [13]
3 years ago
6

Jenny is a 60% free-throw shooter. She gets to shoot a second free throw if and only if she makes her first shot. She can score

0 points (if she misses her first shot), 1 point (she makes her first but misses her second), or 2 points (she makes both shots).
Suppose Jenny gains confidence after making her first free throw and the probability of her making the second free throw goes up to 70%. Now, what number of points is Jenny most likely to make when she shoots a one-and-one?
Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

hi

Step-by-step explanation:

Andrew [12]3 years ago
3 0
If the probability of each of her shots going in is higher than 50% then the highest probability scenario is that she scores both
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A number is 6 greater than 1/2 another number. If the sum of the numbers is 21,find the numbers.
Fed [463]
X = (1/2)y + 6
x + y = 21

Substitute (1/2)y + 6 as x into the equation x + y = 21 since x = (1/2)y + 6.
[(1/2)y + 6] + y = 21
0.5y + 6 + y = 21
1.5y = 15
y = 10

Same thing, now substitute 10 as y in the other equation.
x + y = 21
x + (10) = 21
x = 11

7 0
3 years ago
Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the
galina1969 [7]

Answer:

a. The margin of error is 2.29.

b. 19.23 to 23.81

Step-by-step explanation:

The sample size is n=64.

We start by calculating the sample mean and standard deviation with the following formulas:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}

The sample mean is M=21.52.

The sample standard deviation is s=6.89.

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{6.89}{\sqrt{64}}=\dfrac{6.89}{8}=0.861

The degrees of freedom for this sample size are:

df=n-1=64-1=63

The t-value for a 99% confidence interval and 63 degrees of freedom is t=2.656.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.656 \cdot 0.861=2.29

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 21.52-2.29=19.23\\\\UL=M+t \cdot s_M = 21.52+2.29=23.81

The 99% confidence interval for the mean is (19.23, 23.81).

5 0
3 years ago
Match each function with its graph.
Semmy [17]

Answer:

66) C

67) D

68) A

69) B

Step-by-step explanation:

figure x out first for example in q 66

x=-1 , x =5

then look at the graph which graph pf those meets with those points and soo on.

6 0
3 years ago
Slope is - 4 and the line passes through the point (1,3 )​
Sergeeva-Olga [200]
Y = -4x + 7
This is the equation of the line. The slope is -4. The Y- intercept is 7
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M.) A typical tip in a restaurant is 15% of the
Delvig [45]
The tip should be 18.75
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