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4 years ago

Find the missing value. -8 = 6 + ___

2 answers:

8 0

The right answer is (-14).

Here, If we solve 6+(-14) then it equals to -8.

Hope it will help u..

Inga [223]4 years ago

7 0

-14 is the missing value

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Songs of Experience, by William Blake, is a book of poems that

cluponka [151]

The Songs of Experience, by William Blake, is a book of poems that explores the darker side of human nature (D).
William Blake compares the innocent world of a child to the dark, corrupt and repressive world of an adult. Some of the poems in the collection speak of the innocence of childhood while other poems speak of the harshness and darkness of the adult world. This collection of poems as a whole represents the two sides of human nature.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B3a-%283-4a%7D" id="TexFormula1" title="\frac{6}{3a-(3-4a}" alt="\frac{6}{3a-(

seropon [69]

A=1 is the awnser for this one

5 0

3 years ago

Which ordered pair is generated from the equation shown below? y = 3x + 2 A. (3, 11) B. (3, 9) C. (5, 15) D. (2, 4)

borishaifa [10]

Answer:

y = 3x + 2

There slope is 3 and intercept is 2.

First find what are the 2 pair that given by slope =3

First consider A. (3, 11) and B. (3, 9)

Tan α = \fraction(11-9)(3-3)

It is undefine.

Next consider A. (3, 11) and BC (5,15)

Tan α = \fraction(15-11)(5-3)

Next consider A. (3, 11) and D. (2,4)

Tan α = \fraction(11-4)(3-2)

Next consider B (3, 9) and C. (5,15)

Tan α = \fraction(15-9)(5-3)

So this is ordered pair is generated from slope =3

Step-by-step explanation:

8 0

3 years ago

Please solve asap thanks

natima [27]

Answer:

6x+36=180

6x=144

x=24

Step-by-step explanation:

this is the correct answer

8 0

3 years ago

Read 2 more answers

HELPPPP!!!!!!!! 100 points!!!! I need help on 37-39 thanks!

____ [38]

Answer:

Part 37)

a) Point-slope form $y-5=(1)(x-3)$

b) Slope intercept form $y=x+2$

c) Standard form $x-y=-2$

Part 38)

a) Point-slope form $y-2=0.25(x+4)$

b) Slope intercept form $y=0.25x+3$

c) Standard form $x-4y=-12$

Part 39)

a) Point-slope form $y-3=2(x-1)$

b) Slope intercept form $y=2x+1$

c) Standard form $2x-y=-1$

Step-by-step explanation:

Part 37) Line passing through point (3,5) and slope of 1

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute the given values

$y-5=(1)(x-3)$

$y-5=(x-3)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

Substitute the given values in the equation and solve for b

$5=(1)(3)+b$

$5=3+b$

$b=5-3$

$b=2$

substitute

$y=x+2$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=x+2$

Convert to standard form

Subtract y both sides

$y-y=x+2-y$

$0=x+2-y$

Subtract 2 both sides

$-2=x+2-y-2$

$-2=x-y$

Rewrite

$x-y=-2$ ----> equation in standard form

Part 38) Line passing through points (-4,2) and (0,3)

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

Find the slope m

$m=(3-2)/(0+4)=1/4=0.25$

with the slope m=0.25 and point (-4,2)

substitute the given values

$y-2=0.25(x+4)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=0.25$

$b=3$ -----> the y-intercept is the point (0,3)

Substitute the given values in the equation

$y=0.25x+3$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=0.25x+3$

Convert to standard form

Multiply by 4 both sides to remove the decimal number

$4y=x+12$

Subtract 4y both sides

$4y-4y=x+12-4y$

$0=x+12-4y$

Subtract 12 both sides

$-12=x+12-4y-12$

$-12=x-4y$

Rewrite

$x-4y=-12$ ----> equation in standard form

Part 39) Line passing through points (1,3) and (2,5)

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

Find the slope m

$m=(5-3)/(2-1)=2/1=2$

with the slope m=2 and point (1,3)

substitute the given values

$y-3=2(x-1)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

with the slope m=2 and point (1,3)

Substitute the given values and solve for b

$3=(2)(1)+b$

$3=2+b$

$b=3-2=1$

substitute

$y=2x+1$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=2x+1$

Convert to standard form

Subtract y both sides

$y-y=2x+1-y$

$0=2x+1-y$

Subtract 1 both sides

$-1=2x+1-y-1$

$-1=2x-y$

Rewrite

$2x-y=-1$ ----> equation in standard form

8 0

4 years ago