What is the 32nd term of the arithmetic sequence where a1 = 12 and a13 = -60
2 answers:
Answer:
- 174
Step-by-step explanation:
The nth term of an arithmetic sequence is given as
Tn = a + (n - 1)d
where Tn is the nth term
a is the first term , n is the number of term and d is the common difference. As such,
a13 = a + (13 - 1)d
= a + 12d
Given that a1 = 12 and a13 = -60
-60 = 12 + 12d
12d = -72
d = -6
Hence a32 which is the 32nd term
= 12 + (32 - 1)-6
= 12 + (-186)
= - 174
Answer:
The 32nd term of Arithmetic sequence is -174
Step-by-step explanation:
Given:
We are given two term of the Arithmetic sequence.
Formula:
For
For
Using two equation solve for a and d
We need to find 32nd term
Hence, The 32nd term of Arithmetic sequence is -174
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