Ask question

Ask question

All categories

3 years ago

15

4. Cynthia spent 3/4 of her time at the gym on the stair machine. She spent a total of 21 3/4 minutes on the stair machine. Cynt

hia was at the gym for ____ minutes.

1 answer:

VashaNatasha [74]3 years ago

6 0

Answer:

Step-by-step explanation:

29 min

You might be interested in

20 POINTSS!! Choose the fraction(s) equivalent to the given fraction. -1/7 Select all that apply A. -1/7 B. 1/-7 C. 1/7 D. -1/-7

sladkih [1.3K]

Answer:

A and B.

Step-by-step explanation:

So we want to select the fractions that equal -1/7.

Let's go through each of the answer choices.

A)

A is -1/7, the exact same.

A is correct.

B)

B is 1/-7.

We can move the negative to the top.

So, 1/-7 is equivalent to -1/7.

B is also correct.

C)

C is 1/7

There are no negatives whatsoever.

C is not correct.

D)

We have -1/-7.

Again, move the negative to the top. We will have:

-(-1)/7

The two negatives cancel:

=1/7.

So, D is not correct.

Our answers are A and B.

5 0

3 years ago

What are all the shapes that are used to create the net of a cylinder

Ksenya-84 [330]

2 circles and for the part in the middle if you look at it as a net it will be a rectangle just rolled up. That is called a lateral surface or a lateral face

6 0

3 years ago

Read 2 more answers

A water tank has a square base of area 5 square meters. Initially the tank contains 70 cubic meters. Water leaves the tank, star

ANEK [815]

Answer:

$9.2\ \text{m}$

Step-by-step explanation:

$b$ = Surface area of base = 5 square meters

Volume of water in tank = 70 cubic meters

The rate at which the volume is reducing is

$\dfrac{dV}{dt}=2+4t\\\Rightarrow dV=2+4tdt$

Integrating from $t=0$ to $t=3$

$V=\int^3_0(2+4t)dt\\\Rightarrow V=2t+2t^2|_0^3\\\Rightarrow V=2\times 3+2\times 3^2-0\\\Rightarrow V=24$

Volume of water remaining in the tank is $70-24=46\ \text{m}^3$

Suface area of base $\times$ depth = Volume

$5\times d=46\\\Rightarrow d=\dfrac{46}{5}\\\Rightarrow d=9.2\ \text{m}$

The depth of the water remaining in the tank is $9.2\ \text{m}$ .

3 0

3 years ago

Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =

Strike441 [17]

Answer:

The volume is:

$\displaystyle\frac{37\pi}{10}$

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

$\displaystyle\int_a^b\pi r^2dx$

Notice here the radius of the washer is the difference of the given curves:

$x-\sqrt{x}$

So the integral becomes:

$\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx$

We solve it:

Factor $\pi$ out and distribute the exponent (you can use FOIL):

$\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx$

Notice: $x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}$

So the integral becomes:

$\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx$

Then using the basic rule to evaluate the integral:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4$

Simplifying a bit:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4$

Then plugging the limits of the integral:

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Taking the root (rational exponents):

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Then doing those arithmetic computations we get:

$\displaystyle\frac{37\pi}{10}$

6 0

3 years ago

Only need 3.. pls help!!!

Natalka [10]

Answer: I’m not really sure what the correct answer is if you could help that would be great so let me know

Step-by-step explanation:

6 0

3 years ago