Answer:
g(-1 )=-1 and g(2)+g(1)=7
Step-by-step explanation:
If g(x) = x^3+x^2-x-2 find g(-1)
if we find g(-1)
we substitute all the x's in the function with -1
-1^3+-1^2-(-1)-2
-1^3 = -1
-1^2 = 1
-1+1+1-2
(two minuses make a plus)
-1+1 = 0
0+1 = 1
1-2 = -1
if x=-1, g(-1) is -1
g(2)+g(1)
substitute the x's in the function with 2 and 1 and add your results
2^3+2^2-2-2
2^3 = 8, 2^2 = 4
8+4-2-2
8+4= 12, 12-2 = 10, 10-2 = 8
g(2)=8
g(1) now
1^3 + 1^2-1-2
1^3=1, 1^2 = 1
1+1-1-2
1+1 = 2, 2-1 = 1, 1-2 = -1
g(3) = -1
g(2) (which equals 8) + g(3) (which equals -1) =
8+(-1) = 7
g(2)+g(3)=7
<span> x = 5/6 = 0.833.................</span>
It depends on H(m) what is it?
1. Answer: Vertical shift up 3 units and vertical stretch by factor of 2
<u>Step-by-step explanation:</u>
f(x) = √x
g(x) = 2√x + 3
- adding 3 is a vertical shift up 3 units
- multiplying by 2 is a vertical stretch by factor of 2
2. Answer: Domain: [0, ∞)
Range: [3, ∞)
<u>Step-by-step explanation:</u>
g(x) = 2√x + 3
Domain: The restriction on "x" is that the radical must be greater than or equal to 0. So, x ≥ 0 Interval Notation: [0, ∞)
Range: Since the radical must be greater than or equal to 0, then 2√x is also greater than or equal to 0. Add 3 to that and y ≥ 3. Interval Notation: [3, ∞)
Answer:
-70003
Step-by-step explanation:
-70000 - 3 = - 70003
