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babymother [125]
3 years ago
12

It is desired to determine the concentration of arsenic in a lake sediment sample by means of neutron activation analysis. The n

uclide captures a neutron to form , which in turn undergoes β decay. The daughter nuclide produces the characteristic γ rays used for the analysis. What is the daughter nuclide?

Chemistry
1 answer:
Artyom0805 [142]3 years ago
5 0

Answer:

The daughter nuclide is selenium; 76:34 Se

Explanation:

The complete question is as follows;

is desired to determine the concentration of arsenic in a lake sediment sample by means of neutron activation analysis. The nuclide 75:33 As captures a neutron to form 76:33 As, which in turn undergoes beta decay. The daughter nuclide produces the characteristic gamma rays used for the analysis. What is the daughter nuclide?

solution:

Please check attachment for decay equations and explanations

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3 years ago
What is a realistically possible mass number for an isotope of the above Sulfur?
Irina18 [472]
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3 years ago
the elements fluorine,chlorine,bromine,and iodine are all found in the same group on the table. these elements are grouped toget
madreJ [45]

Answer:

Fluorine, chlorine, bromine and iodine are grouped together because they have the same number of valence electrons.

Explanation:

Fluorine, chlorine, bromine and iodine are all found in group 7, which is the second-last column from the right. Group 7 elements are also called the "Halogens" family.

The group number also tells you the number of valence electrons that the elements have in that group. Valence electrons mean the outermost electrons (See picture).

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8 0
3 years ago
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Please help asap! This is the last question for my chemistry test!
stepan [7]

Answer:

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Explanation:

4 0
3 years ago
What is [h3o ] in a solution of 0.25 m ch3co2h and 0.030 m nach3co2?
Brilliant_brown [7]
Hello!

To determine [H₃O⁺], we need to apply the Henderson-Hasselback equation, since this is a case of an acid and its conjugate base:

pH=pKa+log( \frac{[A^{-}] }{[HA]} )

pH=4,76+log( \frac{0,030M}{0,25M} ) \\  \\ pH=3,84

Now, we use the definition of pH and clear [H₃O⁺] from there:

pH=-log[H_3O^{+}]

[H_3O^{+}] = 10^{-pH} =10^{-3,84}=0,00014 M

So, the [H₃O⁺] concentration is 0,00014 M

Have a nice day!
4 0
3 years ago
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