It is desired to determine the concentration of arsenic in a lake sediment sample by means of neutron activation analysis. The n
uclide captures a neutron to form , which in turn undergoes β decay. The daughter nuclide produces the characteristic γ rays used for the analysis. What is the daughter nuclide?
1 answer:
Answer:
The daughter nuclide is selenium; 76:34 Se
Explanation:
The complete question is as follows;
is desired to determine the concentration of arsenic in a lake sediment sample by means of neutron activation analysis. The nuclide 75:33 As captures a neutron to form 76:33 As, which in turn undergoes beta decay. The daughter nuclide produces the characteristic gamma rays used for the analysis. What is the daughter nuclide?
solution:
Please check attachment for decay equations and explanations
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Answer:
Explanation:
Hello,
In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:
In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:
Therefore, the percent yield is:
Best regards.
%yield = 54.6%
<h3>Further explanation</h3>Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated
(theoretical)
General formula:
Percent yield = (Actual yield / theoretical yield )x 100%
<h3 />Reaction
2ZnS+3O₂ ⇒ 2ZnO+2SO₂
MW ZnS = 97.474 g/mol
- mol ZnS
MW ZnO = 81.38 g/mol
- mol ZnO (from mol ZnS as limiting reactant, O₂ excess)
- Actual ZnO produced
Theoretical production = 125.388
- %yield